在flutter应用程序中使用SnackBar时,出现了上下文错误。所以我为此使用了一个buildcontext ctx,现在出现了这个错误。任何提示如何解决此问题?
这是我遇到的错误:-
E / flutter(30109):[错误:flutter / lib / ui / ui_dart_state.cc(157)]未处理的异常:'package:flutter / src / material / scaffold.dart':失败的断言:1452行pos 12 :'context!= null':不正确。
E / flutter(30109):#0 _AssertionError._doThrowNew(dart:core-patch / errors_patch.dart:42:39) E / Flutter(30109):#1 _AssertionError._throwNew(dart:core-patch / errors_patch.dart:38:5) E / flutter(30109):#2 Scaffold.of(包装:flutter / src / material / scaffold.dart:1452:12) E / flutter(30109):#3 _RegistrationScreenState._trySubmit(软件包:flash_chat / screens / registration_screen.dart:44:18) E / flutter(30109):
-这是.dart文件。
class RegistrationScreen extends StatefulWidget {
static const String id = 'registration_screen';
@override
_RegistrationScreenState createState() => _RegistrationScreenState();
}
class _RegistrationScreenState extends State<RegistrationScreen> {
final _auth = FirebaseAuth.instance;
bool showSpinner = false;
String email;
String password;
String username;
BuildContext ctx;
final _formKey = GlobalKey<FormState>();
void _trySubmit() async {
final isValid = _formKey.currentState.validate();
FocusScope.of(context).unfocus();
if (isValid) {
_formKey.currentState.save();
try {
final newUser = await _auth.createUserWithEmailAndPassword(
email: email, password: password);
if (newUser != null) {
Navigator.pushNamed(context, ChatScreen.id);
}
} on PlatformException catch (e) {
var message = 'An error occurred, Please check your credentials!';
if (e.message != null) {
message = e.message;
}
Scaffold.of(ctx).showSnackBar(
SnackBar(
content: Text(message),
backgroundColor: Theme.of(ctx).errorColor,
),
);
} catch (e) {
print(e);
}
}
}
@override
Widget build(BuildContext context) {
return Scaffold(
backgroundColor: Colors.white,
body: ModalProgressHUD(
inAsyncCall: showSpinner,
child: Padding(
padding: EdgeInsets.symmetric(horizontal: 24.0),
child: Form(
key: _formKey,
child: Column(
mainAxisAlignment: MainAxisAlignment.center,
crossAxisAlignment: CrossAxisAlignment.stretch,
children: <Widget>[
Flexible(
child: Hero(
tag: 'logo',
child: Container(
height: 200.0,
child: Image.asset('images/logo.png'),
),
),
),
SizedBox(
height: 48.0,
),
TextFormField(
validator: (value) {
if (value.isEmpty || !value.contains('@')) {
return 'Please enter a valid Email address.';
}
return null;
},
keyboardType: TextInputType.emailAddress,
textAlign: TextAlign.center,
onSaved: (value) {
email = value;
},
decoration:
kTextFieldDecoration.copyWith(hintText: 'Email Address'),
),
SizedBox(
height: 8.0,
),
TextFormField(
validator: (value) {
if (value.isEmpty || value.length < 4) {
return 'Please enter at least 4 characters.';
}
return null;
},
textAlign: TextAlign.center,
onSaved: (value) {
username = value;
},
decoration:
kTextFieldDecoration.copyWith(hintText: 'Username'),
),
SizedBox(
height: 8.0,
),
TextFormField(
validator: (value) {
if (value.isEmpty || value.length < 7) {
return 'Password must be at east 7 characters long.';
}
return null;
},
obscureText: true,
textAlign: TextAlign.center,
onSaved: (value) {
password = value;
},
decoration:
kTextFieldDecoration.copyWith(hintText: 'Password'),
),
SizedBox(
height: 24.0,
),
RoundedButton(
title: 'Register',
colour: Colors.blueAccent,
onPressed: _trySubmit,
),
],
),
),
),
),
);
}
}
答案 0 :(得分:0)
用Builder包裹脚手架的主体
Scaffold(
body:Builder(builder:(BuildContext context){
return ModalProgressHUD(...);
}),
)
在_trySubmit函数中传递上下文
RoundedButton(
title: 'Register',
colour: Colors.blueAccent,
onPressed: (){
_trySubmit(context);
},
),
您的trySubmit应该看起来像这样
void _trySubmit(scaffContext) async {
然后将这个scaffContext传递给Scaffold.of(scaffContext)。用scaffContext替换ctx。
答案 1 :(得分:0)
First option : Wrap your body with Builder widget like :
=> Builder : (builder : (context) => yourBody(),),
Second option : Create a global key for reaching your context state such as
=> GlobalKey<ScaffoldState> _scaffoldKey = GlobalKey<ScaffoldState>();
and Scaffold(key : _scaffoldKey) then use it whereever you want like
=> _scaffoldKey.currentState.showSnackBar(SnackBar(content: Text("Scaffold key"),));