Question

我目前只是在弄乱乱序编程的窍门，所以我可以制作一个实际的游戏，但是遇到一个问题，当我尝试使python查找文件时，出现了我不理解的Unicode错误。这是代码：（错误附加为图像）：

import discord

import asyncio

from discord.ext import commands

from PIL import Image

bot = discord.Client()

class MyClient(discord.Client):
    async def on_ready(self):
        print('Logged on as', self.user)

    async def on_message(self, message):
        # don't respond to ourselves
        if message.author == self.user:
            return
        
        if message.content == "Big red button":
            await message.channel.send("Oh no i died")
            quit()
        elif message.content == "Cinnamon roll":
            await message.channel.send("Here you go")
            await channel.send(file=discord.File('C:\Users\User\Desktop\Python\Cinnamon_Roll.png'))
            
client = MyClient()
client.run('TOKEN')

Answer 1

我没有看到您的错误图片，但是您的路径中包含无效的转义序列。用以下内容替换第26行：

await channel.send(file=discord.File('C:\\Users\\User\Desktop\Python\Cinnamon_Roll.png'))

Answer 2

如果这很简单，则无需使用类。请记住，任何人都可以像这样阻止机器人，您可以进行额外检查

if message.content == "Big red button" and message.author.id == 'OWNER_ID_HERE':

import discord
from discord.ext import commands

bot = commands.Bot(command_prefix="$")

@bot.event
async def on_ready():
    print("Logged in as")
    print(bot.user.name)
    print("------")

@bot.event
async def on_message(message):
    # don't respond to ourselves
    if message.author == bot.user:
        return

    if message.content == "Big red button":
        await message.channel.send("Oh no i died")
        await bot.logout()
    elif message.content == "Cinnamon roll":
        await message.channel.send("Here you go")
        await message.channel.send(file=discord.File('C:\Users\User\Desktop\Python\Cinnamon_Roll.png'))
        
bot.run('TOKEN_HERE')

Answer 3

您也可以执行此操作，而不是用另一个斜杠转义斜杠。

await channel.send(file=discord.File(r'C:\Users\User\Desktop\Python\Cinnamon_Roll.png'))

保留r符号会使它变原始。

python不接受\的原因是因为斜杠是特殊的并且用于unicode字符

Python在文件位置遇到了unicode问题

3 个答案: