Question

我有模型票，用户可以在其中解释问题。

Ticket.php

class Ticket extends Model
{
    protected $table = 'tickets';
    /**
     * @var array
     */
    protected $guarded = [];

    /**
     * @var array
     */
    protected $hidden = [
        'created_at', 'updated_at'
    ];


    public function ticket_replies()
    {
        return $this->hasMany(TicketReply::class, 'ticket_id');
    }

    public function ticket_assigned_agents()
    {
        return $this->hasMany(TicketAssignedAgent::class, 'ticket_id');
    }
}

还有另一种模式 TicketReply.php

class TicketReply extends Model
{
    protected $table = 'ticket_replies';
    /**
     * @var array
     */
    protected $guarded = [];

    /**
     * @var array
     */
    protected $hidden = [
        'created_at', 'updated_at'
    ];

    public function staffs(){
        return $this->belongsTo(Staff::class,'user_id');
    }
    public function ticket()
    {
        return $this->belongsTo(Ticket::class, 'ticket_id');
    }
}

现在我想从票证回复中获取工作人员姓名

查询

public function getReplies($ticket_id)
    {
        $ticket =  Ticket::where('id',$ticket_id)->with('ticket_replies')->first();
        return response()->json($ticket);
    }

我想通过ajax成功从TicketReply模型获取人员姓名。

$.each(ticket.ticket_replies, function(index, reply) {
    console.log(reply.staffs.name);
}

但是它不起作用。我该怎么办？

Answer 1

渴望加载嵌套关系

public function getReplies($ticket_id)
{
    $ticket =  Ticket::where('id',$ticket_id)->with(['ticket_replies','ticket_replies.staffs'])->first();
    return response()->json($ticket);
}

然后执行与您相同的操作

$.each(ticket.ticket_replies, function(index, reply) {
    console.log(reply.staffs.name);
}

如何在laravel中获取有关ajax请求的嵌套关系记录？

1 个答案: