Question

我有这段代码：

Module Module1
    Dim x As Integer = 1
    Dim y As Integer = 1
    Dim arr(x, y) As String

    Sub Main()
        x += 2
        y += 3

        For ix = 0 To x
            For iy = 0 To y
                arr(ix, iy) = String.Format("{0}:{1}", ix, iy)
            Next
        Next

        For ix = 0 To x
            For iy = 0 To y
                Console.WriteLine(arr(ix, iy))
            Next
        Next

        Console.Read()
    End Sub

End Module

有了它，我试图改变数组维度的上限。但是我得到了这个错误：“索引超出了数组的范围”。我做错了什么？

Answer 1

您无法像.NET中那样更改数组的上限。如果您需要一个动态大小的数组，我建议您查看List因为它允许您完成所有这些。

你会想做类似的事情：

Dim yourStrings AS List(Of List(Of String)) = New List(Of New List(Of String)

将其转换为二维数组：

Dim maxListLength As Integer = 0
For Each subList In yourStrings
    maxListLength = If(subList.Length > maxListLength, subList.Length, maxListLength)
Next

Dim yourArray(yourString.Length - 1, maxListLength -1) As String

Dim x As Integer = 0
Dim y As Integer = 0

For Each subList In yourString
    For Each str In subList
        yourArray(x, y) = str
        y = y + 1
    Next
    x = x + 1
Next

从2-D到List（List（Of String））

Dim yourList As List(Of List(Of String)) = New List(Of List(Of String))

For i = 0 To ArrayXSize
    Dim thisXString = New List(Of String)
    For j = 0 To ArrayYSize
       thisXStrings.Add(yourArray(i,j))
    Next
    yourList.Add(thisXStrings)  
Next

Answer 2

您可以根据需要使用ReDim重新分配内存。

Answer 3

如果使用维x和y声明数组，要使用出站值，必须使用redim（）命令重新排列数组：

MSDN Redim Command Doc

示例：

Dim intArray(10, 10, 10) As Integer ReDim Preserve intArray(10, 10, 20)

Answer 4

我自己做了这个：

   Private Function MultiReDim(ByVal a As Array, ByVal dimOne As Short, ByVal dimTwo As Short) As String(,)
        Dim newArr(dimOne, dimTwo) As String
        For x = 0 To newArr.GetUpperBound(0)
            For y = 0 To newArr.GetUpperBound(1)
                If x <= a.GetUpperBound(0) AndAlso y <= a.GetUpperBound(1) Then
                    newArr(x, y) = a(x, y)
                Else
                    newArr(x, y) = Nothing
                End If

            Next
        Next

        Return newArr
    End Function

它适用于2D数组，但可以通过添加尺寸的ParamArray进行修改以使用无限数量的数组。

Answer 5

我不知道何时引入了这种语法，但您可以使用以下命令定义具有动态大小的数组：

Dim arr As String(,) = New String(x,y){}

或只是

Dim arr = New String(x,y){}

或使用原始示例

Module Module1

    Dim x As Integer = 1
    Dim y As Integer = 1
    Dim arr(x, y) As String

    Sub Main()
        x += 2
        y += 3

        arr = New String(x,y){}

        For ix As Integer = 0 To x
            For iy As Integer = 0 To y
                arr(ix, iy) = String.Format("{0}:{1}", ix, iy)
            Next
        Next

        For ix As Integer = 0 To x
            For iy As Integer = 0 To y
                Console.WriteLine(arr(ix, iy))
            Next
        Next

        Console.Read()
    End Sub

End Module

（未经测试）。

我认为这种语法比旧的（VB6风格）ReDim语句更好。

动态多维数组问题

5 个答案: