Question

示例代码：

NoClassDefFoundError:org/mockito/exceptions/Reporter

添加到.plist文件中

let sampleURL = "http://Hello/site/link?id=MTk=&fid=MTA="
let urlWhats = "whatsapp://send?text=\(sampleURL)"
if let urlString = urlWhats.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed) {
   if let whatsappURL = NSURL(string: urlString) {
      if UIApplication.shared.canOpenURL(whatsappURL as URL) {
           UIApplication.shared.open(whatsappURL as URL)
      }
      else {
           // Open App Store.
      }
   }
}

面对问题是与＆

之后的＆文本共享链接时

对于上面的url文本，例如 http：// Hello / site / link？id = MTk =

预先感谢

Answer 1

URL的不同部分具有不同的编码规则。 addingPercentEncoding很难正确使用。通常，您不应尝试对自己的URL进行编码。让系统使用URLComponents为您做到这一点：

//For the constant part of the link, it's fine to just use a string
var sample = URLComponents(string: "whatsapp://send")!

// Then add a query item
sample.queryItems = [URLQueryItem(name: "text", value: "http://Hello/site/link?id=MTk=&fid=MTA=")]

// Extract the URL, which will have the correct encoding
print(sample.url!)
// whatsapp://send?text=http://Hello/site/link?id%3DMTk%3D%26fid%3DMTA%3D

Answer 2

尝试直接初始化为 URL 而不是 NSURL

let whatsappURL = URL(string: urlString)

，也许可以使用完成处理程序进行进一步调试

UIApplication.shared.open(whatsappURL, options: [:], completionHandler: nil)

Answer 3

经过研究和测试，我发现在.urlQueryAllowed中使用 AllowedCharacters 时，将允许URL并且URL不变，这就是发生此问题的原因。

仅在文本上使用 .init() ，如下所示，whatsapp://send?text= 像下面一样

let sampleURL = "http://Hello/site/link?id=MTk=&fid=MTA="
if let urlString = sampleURL.addingPercentEncoding(withAllowedCharacters: .init()) {
    let urlWhats = "whatsapp://send?text=\(urlString)"
    if let whatsappURL = NSURL(string: urlWhats) {
       if UIApplication.shared.canOpenURL(whatsappURL as URL) {
            UIApplication.shared.open(whatsappURL as URL)
       }
    }
}

链接中包含“＆”时，WhatsApp共享无法正常工作

3 个答案: