Question

这是我的代码

const NewVerificationCode = () => {
  const { loading, error, data = {}, refetch } = useQuery(CONFIRMATION_CODE, {
    skip: true,
    notifyOnNetworkStatusChange: true,
    fetchPolicy: "no-cache",
  });

  return <div onClick={() => refetch()}>CONFIRMATION</div>;
};

const CONFIRMATION_CODE = gql`
  query {
    my {
      sendNewTokenForConfirmation
    }
  }
`;

我提出请求时遇到错误

未捕获的TypeError：无法读取未定义的属性“ refetch”

Answer 1

https://pastebin.com/gEF5s5Yc #include "classes.h" void Library::check_Out(Patron& person, Book& a){ if (check_Book(a) && check_User(person)) { if (!person.check_If_Owes_Fee()) { a.checkOut(); Transaction person.get_Patron_Name(); //error here } else cout << "Can't perform operation. User owes a fee"; } else cout << "Invalid, user or book not in library"; }

似乎您试图从未定义的#include "classes.h" int main() { Book one("123H", "Hey", "Cool", Date(31, 12, 2020), Genre::FICTION); Book two("123H", "Hey", "Cool", Date(31, 12, 2020), Genre::CHILDREN); operator<<(cout, one); return 0; }错误“逃脱”-不建议使用的方法...使用

data = {}

...在主要内容之前或

data

if(loading) return <Loading />选项阻止执行钩子，因此不可能if(data) return <div onClick={() => refetch()}>CONFIRMATION</div>; return null;。只需使用skip或使用某种状态来控制refetch选项，例如：

useLazyQuery

无法读取未定义的属性“ refetch”

1 个答案: