我想返回按天与Laravel Eloquent分组的每条记录的最小值和最大值,所以就这样:
表结构:费率
id buy_rate sell_rate market_currency_id created_at
== ======== ========= ================== ==========
1 10 7 44 2020-10-10
2 10 9 44 2020-10-10
3 10 8 44 2020-10-10
4 10 12 44 2020-10-11
5 10 14 44 2020-10-11
6 10 13 44 2020-10-11
现在我正在获取这样的数据:
$rates = Rate::
select('sell_rate', \DB::raw("DATE_FORMAT(created_at, %Y-%m-%d) day))
->where('market_currency_id', '=', 44)
->whereBetween('created_at', [2020-10-10, 2020-10-11])
->orderBy('created_at', 'ASC')
->get()
->toArray();
上面的代码返回:
0 => array:2 [▼
"sell_rate" => "8"
"day" => "2010-10-10"
]
1 => array:2 [▼
"sell_rate" => "12"
"day" => "2010-10-11"
]
现在,我想要得到的是这样的东西:
0 => array:2 [▼
"sell_rate" => "8"
"day" => "2010-10-10"
"min_rate" => "7"
"max_rate" => "9"
]
1 => array:2 [▼
"sell_rate" => "13"
"day" => "2010-10-11"
"min_rate" => "12"
"max_rate" => "14"
]
我尝试了很多方法,但是我没有得到想要的东西,我尝试了这样的原始选择:
$rates = Rate::
select('sell_rate', \DB::raw("DATE_FORMAT(created_at, %Y-%m-%d) day))
->selectRaw("MIN(sell_rate) AS min_rate, MAX(sell_rate) AS max_rate")
->where('market_currency_id', '=', 44)
->whereBetween('created_at', [2020-10-10, 2020-10-11])
->orderBy('created_at', 'ASC')
->get()
->toArray();
但是无法得到我想要的东西,我也不能分开做,因为有成千上万的行,谢谢!!
答案 0 :(得分:4)
您还需要按天分组:
$rates = Rate::select(DB::raw("DATE_FORMAT(created_at, %Y-%m-%d) day"))
->selectRaw("MIN(sell_rate) AS min_rate, MAX(sell_rate) AS max_rate")
->where('market_currency_id', '=', 44)
->whereBetween('created_at', ['2020-10-10', '2020-10-11'])
->groupBy(DB::raw('day'))
->orderBy(DB::raw('day'))
->get()
->toArray();
答案 1 :(得分:1)
您可以尝试以下方法:
$rates = Rate::
select('sell_rate', \DB::raw("DATE_FORMAT(created_at, %Y-%m-%d) day"), \DB::raw("MIN(sell_rate) as min_rate"), \DB::raw("MAX(sell_rate) as max_rate"))
->where('market_currency_id', '=', 44)
->whereBetween('created_at', [2020-10-10, 2020-10-11])
->orderBy('created_at', 'ASC')
->groupBy(DB::raw('day'))
->get()
->toArray();