Question

当输入为：

时，我正试图退出while循环

BYE
  BYE
  BYE

而不是这个：

BYE BYE BYE

代码是：

my_reply = ((word1 = gets) + (word2 = gets) + (word3 = gets))

while my_reply != ((word1 == 'BYE') and (word2 == 'BYE') and (word3 == 'BYE'))
    puts 'Grandma: ...'
    my_reply = ((word1 = gets) + (word2 = gets) + (word3 = gets))
end

puts 'Grandma: ' + 'Fine, sonny, don\'t hang out with your aging grandmother!'.upcase

哪个不行。我需要帮助。

Answer 1

gets也会返回换行符和回车符“\ r \ n”，例如“再见\ r \ n”。这意味着在与其他字符串进行比较之前必须将它们删除。（见String.strip）

while [gets, gets, gets].map(&:strip) != ['BYE', 'BYE', 'BYE']
  puts 'Grandma: ...'
end

puts 'Grandma: ' + 'Fine, sonny, don\'t hang out with your aging grandmother!'.upcase

Answer 2

获取的输入包括换行符（BYE \ n）。 gets.chomp 可以摆脱它。

Answer 3

我不太确定，但您可能正在尝试做类似的事情：

bye_3 = Array.new(3, "BYE")
until Array.new(3){gets.chomp} == bye_3
  puts "Grandma: ..."
end
puts 'Grandma: ' + 'Fine, sonny, don\'t hang out with your aging grandmother!'.upcase

Array.new(3, "BYE")与["BYE", "BYE", "BYE"]相同，Array.new(3){gets.chomp}与[gets.chomp, gets.chomp, gets.chomp]相同。

输入与条件不匹配

3 个答案: