这是我的时间戳=“ 2020-05-29T17:43:39.622832 + 05:30”。如何将其传递给readTimeStamp函数(它将给我非int类型的错误)?
date = DateTime.parse(bookDetails.timestamp);
print(readTimestamp(date));
String readTimestamp(int timestamp) {
var now = DateTime.now();
var date = DateTime.fromMillisecondsSinceEpoch(timestamp * 1000);
var diff = now.difference(date);
String time = '';
if (diff.inSeconds <= 0 ||
diff.inSeconds > 0 && diff.inMinutes == 0 ||
diff.inMinutes > 0 && diff.inHours == 0 ||
diff.inHours > 0 && diff.inDays == 0) {
} else if (diff.inDays > 0 && diff.inDays < 7) {
if (diff.inDays == 1) {
time = diff.inDays.toString() + ' DAY AGO';
} else {
time = diff.inDays.toString() + ' DAYS AGO';
}
} else {
if (diff.inDays == 7) {
time = (diff.inDays / 7).floor().toString() + ' WEEK AGO';
} else {
time = (diff.inDays / 7).floor().toString() + ' WEEKS AGO';
}
}
return time;
}
这是我的函数,可以像3天前一样返回值。
答案 0 :(得分:1)
bool isAfterToday(Timestamp timestamp) {
return DateTime.now().toUtc().isAfter(
DateTime.fromMillisecondsSinceEpoch(
timestamp.millisecondsSinceEpoch,
isUtc: false,
).toUtc(),
);
}
答案 1 :(得分:0)
DateTime.parse
返回一个DateTime
。 readTimestamp
似乎期望从纪元开始的秒数,因此您只需要使用DateTime.millisecondsSinceEpoch
并将毫秒转换为秒:
print(readTimestamp(date.millisecondsSinceEpoch ~/ 1000));
就个人而言,如果您控制readTimestamp
函数,我会将其模棱两可的timestamp
参数重命名为secondsSinceEpoch
,以明确说明其期望值。甚至更好的方法是将其参数更改为直接采用DateTime
而不是执行不必要的DateTime
<=>毫秒<=>秒转换。