Redux useSelector返回未定义的嵌套值

时间:2020-08-13 00:43:23

标签: javascript reactjs react-native react-redux redux-toolkit

我创建了一个客户类型

export interface ICustomer {
  customer_code: string;
  name: string;
}

并将其导入到我的reducer并在该文件中配置我的初始状态

import { createSlice, PayloadAction } from "@reduxjs/toolkit";
import {
  ICustomer,
} from "../types/createInvoice_types";

const InvoiceCustomerState: ICustomer[] = [];

export const createInvoiceCustomerSlice = createSlice({
  name: "CustomerToInvoice",
  initialState: invoiceDetailsState,
  reducers: {
    create: {
      reducer: (state, { payload }: PayloadAction<ICustomer>) => {
        state.push(payload);
      },
      prepare: (customer: Partial<ICustomer>) => ({
        payload: customer,
      }),
    },
    remove: (state) => {
      return InvoiceCustomerState;
    },
  },
});

export const {
  create: addCustomerToInvoice,
  remove: deleteCustomerToInvoice,
} = createInvoiceCustomerSlice.actions;

以及我要使用它的组件中

import {
  useSelector,
  RootStateOrAny,

} from "react-redux";

  const customer = useSelector(
    (state: RootStateOrAny) => state.customerToInvoice
  );
  

当我console.log(customer)得到 [{"code": "123", "name": "Cash Customer"}]

但是当我尝试console.log(customer.name)时我得到undefined

我也尝试过这个,但是我仍然不确定

interface IRootState {
  customer_code: string;
  name: string;
}

 const customer3 = useSelector((state: IRootState) => {
    state.customerToInvoice.name;
  });

console.log(customer3);

有人可以指出我做错了什么吗

1 个答案:

答案 0 :(得分:1)

当我使用console.log(customer)时,我得到[{“ code”:“ 123”,“ name”:“ Cash Customer”}]

但是当我尝试console.log(customer.name)时,我无法定义

答案就在这两句话中。

当您console.log(customer)清楚地显示customer === [{"code": "123", "name": "Cash Customer"}]时,它是其中包含单个对象的数组。

现在,如果您希望打印第一个元素的名称,则应该使用console.log(customer[0].name)而不是console.log(customer.name)