Question

我有一个看起来像这样的DataFrame。

                          time  daysToExp
0   2020-08-11 13:53:57.083388          0
1   2020-08-11 13:53:57.083388          1
2   2020-08-11 13:53:57.083388          3
3   2020-08-11 13:53:57.083388          4
4   2020-08-11 13:53:57.083388          8

我想将daysToExp列添加到time列，并以类似这样的结果结束。

                          time  daysToExp                         Date
0   2020-08-11 13:53:57.083388          0   2020-08-11 13:53:57.083388
1   2020-08-11 13:53:57.083388          1   2020-08-12 13:53:57.083388
2   2020-08-11 13:53:57.083388          3   2020-08-14 13:53:57.083388
3   2020-08-11 13:53:57.083388          4   2020-08-15 13:53:57.083388
4   2020-08-11 13:53:57.083388          8   2020-08-19 13:53:57.083388

我找到的最接近的命令是df['Date'] = df['time'] + pd.DateOffset(days=3)，但它不能在DataFrame中完成整个列。我该怎么办？

Answer 1

您可以使用pd.to_timedelta：

df['time'] + pd.to_timedelta(df['daysToExp'], unit='D')

或等效地：

df['time'] + pd.to_timedelta('1D') * df['daysToExp']

熊猫将不同日期的列添加到日期时间列

1 个答案: