将逗号分隔的值拆分为多列

Question

我正在尝试使用SQL将逗号分隔的列拆分为多个列，以使每个分隔的值都位于Snowflake上自己的列下

这是我的桌子的一个例子

run()

这是我尝试过的：

"2015-01-01","00:52:44",161144,"3.1.0","x86_64","mingw32","Formula","1.1-2","US",1

这给了我错误消息：

SQL编译错误：位置59的语法错误第1行意外 ''日期''。语法错误第1行的位置149意外出现'）'。

Answer 1

您正在寻找split_part

SPLIT_PART(<string>, <delimiter>, <partNumber>)

---

不过请小心列名。其中一些可能是SQL中的保留关键字，并且可能会引发错误

with your_table as 
(select 'date,time,size,r_version,r_arch,r_os,package,version,country,ip_id' as col)

select split_part(col,',',1) as date,
       split_part(col,',',2) as time,
       split_part(col,',',3) as size,
       split_part(col,',',4) as r_version,
       split_part(col,',',5) as r_arch,
       split_part(col,',',6) as r_os,
       split_part(col,',',7) as package,
       split_part(col,',',8) as version,
       split_part(col,',',9) as country,
       split_part(col,',',10) as ip_id
from your_table;