Question

我有一个数组表示法的objects数组。这个数组每次都会有所不同。

我希望能够获得此数组中元素的名称。我遇到的麻烦是返回[object]而不是返回assetA，例如。我知道这是因为assetA本身就是一个对象。

我用来测试它的代码示例是..

//the assetArray will have varying number of elements in the future
var assetArray=[assetX,assetY,assetZ, assetB, assetA];
var testtest=(new String(assetArray));
alert(testtest);
$.each(assetArray,function(intIndex,objValue){
    var test123=(new String(assetArray[intIndex]));
    alert(test123);
});

并且测试资产列表是..

var assetX = {
    assetNumber: "TESTX",
    assetDescription: "FLUX CAPACITOR",
    assetManufacturer: "Honeywell",
    assetCustomer: "MCFLY",
    assetDate: "03/04/1956"
};
var assetY = {
    assetNumber: "C123Y",
    assetDescription: "HOVERBOARD",
    assetManufacturer: "GE",
    assetCustomer: "MCFLY",
    assetDate: "12/03/1945"
};
var assetZ = {
    assetNumber: "9000Z",
    assetDescription: "ROCKETFOOTBALL",
    assetManufacturer: "Fluke",
    assetCustomer: "MCFLY JR.",
    assetDate: "01/05/3030"
};
var assetA = {
    assetNumber: "C34JJXA",
    assetDescription: "TEST DESCRIPTION",
    assetManufacturer: "Elgar",
    assetCustomer: "CUSTOMER1",
    assetDate: "05/09/1923"
};
var assetB = {
    assetNumber: "C892ALB",
    assetDescription: "DMM",
    assetManufacturer: "Agilent",
    assetCustomer: "CUSTOMER2",
    assetDate: "02/12/1986"
};

有没有人使用jQuery遇到过这类问题？

Answer 1

没有对象的名称。有物，完全停止。有零个或多个变量引用给定对象，完全停止。你不能从一个对象转到引用它的变量，句号，新段落。

如果此“名称”是对象本身的重要属性，请将其包含在对象中（添加name字段）或使用关联数组（也称为命名空间，引擎盖下的对象）名称“是关键，资产对象是值而不是数组。

Answer 2

将资产对象作为属性存储在对象中（即使用关联数组而不是序数数组）：

var assets = {
    assetX: {
        assetNumber: "TESTX",
        assetDescription: "FLUX CAPACITOR",
        assetManufacturer: "Honeywell",
        assetCustomer: "MCFLY",
        assetDate: "03/04/1956"
    },
    assetY: {
        assetNumber: "C123Y",
        assetDescription: "HOVERBOARD",
        assetManufacturer: "GE",
        assetCustomer: "MCFLY",
        assetDate: "12/03/1945"
    },
    ...
};

$.each(assets, function (name, asset) {
    // name is the name (e.g. "assetX")
    // asset is the object instance
});

Answer 3

我不确定你想要展示什么。

但您可以只显示对象的各个部分：

//the assetArray will have varying number of elements in the future
var assetArray=[assetX,assetY,assetZ, assetB, assetA];
var testtest=(new String(assetArray));
alert(testtest);
$.each(assetArray,function(intIndex,objValue){
    var test123=objValue.assetNumber; //etc
    alert(test123);
});

Answer 4

我建议使用常规JavaScript对象将对象名称与值匹配。

如何从对象数组中获取名称

4 个答案: