我正在从数据库中检索数据并将其推入数组,然后使用json_encode()以json格式输出。我最终已经有了这种格式的数据。
[
{
"category_id": "1",
"category_name": "Construction Materials"
},
{
"items": [
{
"id": "1",
"item_name": "Wire Mesh",
"price": "459",
"image_url": null
},
{
"id": "2",
"item_name": "Cement",
"price": "700",
"image_url": null
},
{
"id": "3",
"item_name": "Barbed Wire",
"price": "3000",
"image_url": null
},
{
"id": "4",
"item_name": "Iron sheet",
"price": "200",
"image_url": null
}
]
},
{
"category_id": "2",
"category_name": "Plumbing"
},
这是我要实现的目标:
[
{
"category_id": "1",
"category_name": "Construction Materials"
"items": [
{
"id": "1",
"item_name": "Wire Mesh",
"price": "459",
"image_url": null
},
{
"id": "2",
"item_name": "Cement",
"price": "40",
"image_url": null
},
{
"id": "3",
"item_name": "Barbed Wire",
"price": "3000",
"image_url": null
},
{
"id": "4",
"item_name": "Iron sheet",
"price": "200",
"image_url": null
}
]
},
{
"category_id": "2",
"category_name": "Plumbing"
},
如何在php中实现这一目标。是否可以编辑主数组的内容?如何在“ category_name”之后添加“ items” 问候。
答案 0 :(得分:0)
function get_first_property($object) {
$properties = array_keys(get_object_vars($object));
return reset($properties);
}
function object_merge($object1, $object2) {
return (object) array_merge((array) $object1, (array) $object2);
}
// loop through each of the array objects
$previous_first_property = null;
foreach ($array as $i => $object) {
$first_property = get_first_property($object);
// merge if the 1st property is "items", and the previous 1st was "category_id"
if ($first_property == "items" && $previous_first_property == "category_id") {
$array[$i - 1] = object_merge($array[$i - 1], $array[$i]);
unset($array[$i]);
}
$previous_first_property = $first_property;
}
答案 1 :(得分:0)
$array = json_decode($yourJson);
$arrayLength = count($array);
$finalArray = [];
for ($i=0; $i < $arrayLength; $i+=2) {
$finalArray[] = $array[$i] + $array[$i + 1];
}
$backToJson = json_encode($finalArray);
替代Mattijs的答案。