Question

好的，所以我遇到了将文件作为blob插入数据库的问题。我能够将文件上传到我的数据库上的文件夹，但我现在想要将该文件作为blob插入到我的数据库中。我知道这一般不行，但我想做。无论如何我想知道是否有人有任何PHP代码将文件插入blob表？我试过用这个无济于事我可能只是不写SQL语句吗？

<?php 
 $target = "./"; 
 $target = $target . basename( $_FILES['uploadedfile']['name']); 
 $file=($_FILES['uploadedfile']['name']); 
 if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
 echo "The file ".  basename( $_FILES['uploadedfile']['name']).
 " has been uploaded";
 }else{
 echo "There was an error uploading the file, please try again!";
 }
 mysql_connect("localhost","root","");
 mysql_select_db("ivrsupport");
 $sql=mysql_query("insert into CUSTOMER (AUDIO_FILE)values
   ('$file') where PHONE_NUMBER = ('15555215554')");
 $r=mysql_query($sql);
 if(!$r){
 echo "Error in query: ".mysql_error();
 }  
mysql_close();  
?>

Answer 1

我会避免在数据库中存储文件。这就是FileSystems的用途，并且做得更好。博客圈里有数以百万计的帖子解释了为什么不这样做。即使是小型应用程序，我也不会这样做。它只是感觉很脏。数据库中的blob不包含有关文件本身的元数据，因为可以通过多种方式查询FS来获取文件大小，修改时间，权限等信息...我的$ 0.02

Answer 2

你需要将文件读入一个变量然后插入它。给它文件名只会不做。

$fp      = fopen($basename, 'r');
$content = fread($fp, filesize($basename));
fclose($fp);

$sql=mysql_query("insert into CUSTOMER (AUDIO_FILE)values
   ('$content') where PHONE_NUMBER = ('15555215554')");

Answer 3

$ file只包含文件的名称而不是它的内容。

尝试以下方法：

<?php 
 $target = "./"; 
 $target = $target . basename( $_FILES['uploadedfile']['name']); 
 $file=($_FILES['uploadedfile']['name']); 
 $fileContents = file_get_contents($file);
 if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
 echo "The file ".  basename( $_FILES['uploadedfile']['name']).
 " has been uploaded";
 }else{
 echo "There was an error uploading the file, please try again!";
 }
 mysql_connect("localhost","root","");
 mysql_select_db("ivrsupport");
 $sql=mysql_query("insert into CUSTOMER (AUDIO_FILE)values
   ('$fileContents') where PHONE_NUMBER = ('15555215554')");
 $r=mysql_query($sql);
 if(!$r){
 echo "Error in query: ".mysql_error();
 }  
mysql_close();

将文件上传到mySQL数据库。帮助代码

3 个答案: