我有一个包含多个值的枚举:
枚举{value1,value2,value3} myValue;
在我的应用中的某个点,我希望检查枚举的哪个值现在处于活动状态。我正在使用NSLog,但我不清楚如何显示枚举的当前值(value1 / valu2 / valu3 / etc ...)作为NSLog的NSString。
任何?
答案 0 :(得分:83)
我不喜欢将枚举放在堆上,而不提供用于转换的堆函数。这就是我想出的:
typedef enum {value1, value2, value3} myValue;
#define myValueString(enum) [@[@"value1",@"value2",@"value3"] objectAtIndex:enum]
这使得枚举和字符串声明保持紧密,以便在需要时轻松更新。
现在,在代码中的任何地方,您都可以像这样使用枚举/宏:
myValue aVal = value2;
NSLog(@"The enum value is '%@'.", myValueString(aVal));
outputs: The enum value is 'value2'.
为了保证元素索引,您始终可以显式声明开始(或全部)枚举值。
enum {value1=0, value2=1, value3=2};
答案 1 :(得分:55)
在此处回答:a few suggestions on implementation
底线是Objective-C
正在使用常规的旧C
enum
,这只是一组美化的整数。
鉴于此enum
:
typedef enum { a, b, c } FirstThreeAlpha;
您的方法如下所示:
- (NSString*) convertToString:(FirstThreeAlpha) whichAlpha {
NSString *result = nil;
switch(whichAlpha) {
case a:
result = @"a";
break;
case b:
result = @"b";
break;
case c:
result = @"c";
break;
default:
result = @"unknown";
}
return result;
}
答案 2 :(得分:34)
我将介绍我使用的方式,它看起来比以前的答案更好。(我认为)
我想用 UIImageOrientation 进行说明,以便于理解。
typedef enum {
UIImageOrientationUp = 0, // default orientation, set to 0 so that it always starts from 0
UIImageOrientationDown, // 180 deg rotation
UIImageOrientationLeft, // 90 deg CCW
UIImageOrientationRight, // 90 deg CW
UIImageOrientationUpMirrored, // as above but image mirrored along other axis. horizontal flip
UIImageOrientationDownMirrored, // horizontal flip
UIImageOrientationLeftMirrored, // vertical flip
UIImageOrientationRightMirrored, // vertical flip
} UIImageOrientation;
创建一个方法,如:
NSString *stringWithUIImageOrientation(UIImageOrientation input) {
NSArray *arr = @[
@"UIImageOrientationUp", // default orientation
@"UIImageOrientationDown", // 180 deg rotation
@"UIImageOrientationLeft", // 90 deg CCW
@"UIImageOrientationRight", // 90 deg CW
@"UIImageOrientationUpMirrored", // as above but image mirrored along other axis. horizontal flip
@"UIImageOrientationDownMirrored", // horizontal flip
@"UIImageOrientationLeftMirrored", // vertical flip
@"UIImageOrientationRightMirrored", // vertical flip
];
return (NSString *)[arr objectAtIndex:input];
}
您所要做的就是:
命名你的功能。
复制枚举的内容并粘贴在 NSArray * arr = @ [和]之间; return(NSString *)[arr objectAtIndex:input];
放一些@,“和逗号
PROFIT !!!!
答案 3 :(得分:29)
这将由编译器验证,因此您不会意外混淆索引。
NSDictionary *stateStrings =
@{
@(MCSessionStateNotConnected) : @"MCSessionStateNotConnected",
@(MCSessionStateConnecting) : @"MCSessionStateConnecting",
@(MCSessionStateConnected) : @"MCSessionStateConnected",
};
NSString *stateString = [stateStrings objectForKey:@(state)];
var stateStrings: [MCSessionState: String] = [
MCSessionState.NotConnected : "MCSessionState.NotConnected",
MCSessionState.Connecting : "MCSessionState.Connecting",
MCSessionState.Connected : "MCSessionState.Connected"
]
var stateString = stateStrings[MCSessionState.Connected]
答案 4 :(得分:13)
我发现这个website(从下面的例子中可以看出),它为这个问题提供了一个优雅的解决方案。原始帖子来自StackOverflow answer。
// Place this in your .h file, outside the @interface block
typedef enum {
JPG,
PNG,
GIF,
PVR
} kImageType;
#define kImageTypeArray @"JPEG", @"PNG", @"GIF", @"PowerVR", nil
...
// Place this in the .m file, inside the @implementation block
// A method to convert an enum to string
-(NSString*) imageTypeEnumToString:(kImageType)enumVal
{
NSArray *imageTypeArray = [[NSArray alloc] initWithObjects:kImageTypeArray];
return [imageTypeArray objectAtIndex:enumVal];
}
// A method to retrieve the int value from the NSArray of NSStrings
-(kImageType) imageTypeStringToEnum:(NSString*)strVal
{
NSArray *imageTypeArray = [[NSArray alloc] initWithObjects:kImageTypeArray];
NSUInteger n = [imageTypeArray indexOfObject:strVal];
if(n < 1) n = JPG;
return (kImageType) n;
}
答案 5 :(得分:6)
如果我可以提供另一种具有类型检查功能的附加解决方案,如果您在转换,可读性和简洁性方面缺少枚举值,则会发出警告。
对于您的示例:typedef enum { value1, value2, value3 } myValue;
您可以执行此操作:
NSString *NSStringFromMyValue(myValue type) {
const char* c_str = 0;
#define PROCESS_VAL(p) case(p): c_str = #p; break;
switch(type) {
PROCESS_VAL(value1);
PROCESS_VAL(value2);
PROCESS_VAL(value3);
}
#undef PROCESS_VAL
return [NSString stringWithCString:c_str encoding:NSASCIIStringEncoding];
}
作为旁注。这是一种更好的方法来声明你的枚举:
typedef NS_ENUM(NSInteger, MyValue) {
Value1 = 0,
Value2,
Value3
}
通过这种方式,您可以获得类型安全性(在这种情况下为NSInteger
),您可以设置预期的枚举偏移量(= 0
)。
答案 6 :(得分:5)
在某些情况下,当您需要转换枚举时 - &gt; NSString和NSString - &gt;枚举使用typedef和#define(或const NSStrings)而不是enum可能更简单:
typedef NSString * ImageType;
#define ImageTypeJpg @"JPG"
#define ImageTypePng @"PNG"
#define ImageTypeGif @"GIF"
然后只使用“命名”字符串操作,就像使用任何其他NSString一样:
@interface MyData : NSObject
@property (copy, nonatomic) ImageType imageType;
@end
@implementation MyData
- (void)doSomething {
//...
self.imageType = ImageTypePng;
//...
if ([self.imageType isEqualToString:ImageTypeJpg]) {
//...
}
}
@end
答案 7 :(得分:4)
下面的解决方案使用预处理器的stringize运算符,从而提供更优雅的解决方案。它允许您在一个位置定义枚举术语,以便更好地抵御拼写错误。
首先,按以下方式定义枚举。
#define ENUM_TABLE \
X(ENUM_ONE), \
X(ENUM_TWO) \
#define X(a) a
typedef enum Foo {
ENUM_TABLE
} MyFooEnum;
#undef X
#define X(a) @#a
NSString * const enumAsString[] = {
ENUM_TABLE
};
#undef X
现在,按以下方式使用它:
// Usage
MyFooEnum t = ENUM_ONE;
NSLog(@"Enum test - t is: %@", enumAsString[t]);
t = ENUM_TWO;
NSLog(@"Enum test - t is now: %@", enumAsString[t]);
输出:
2014-10-22 13:36:21.344 FooProg[367:60b] Enum test - t is: ENUM_ONE
2014-10-22 13:36:21.344 FooProg[367:60b] Enum test - t is now: ENUM_TWO
@ pixel的回答指出了我正确的方向。
答案 8 :(得分:2)
这是一个即插即用的解决方案,您可以通过简单的复制和粘贴现有定义进行扩展。
我希望你们都觉得它很有用,因为我发现有很多其他的StackOverflow解决方案。
- (NSString*) enumItemNameForPrefix:(NSString*)enumPrefix item:(int)enumItem {
NSString* enumList = nil;
if ([enumPrefix isEqualToString:@"[Add Your Enum Name Here"]) {
// Instructions:
// 1) leave all code as is (it's good reference and won't conflict)
// 2) add your own enums below as follows:
// 2.1) duplicate the LAST else block below and add as many enums as you like
// 2.2) Copy then Paste your list, including carraige returns
// 2.3) add a back slash at the end of each line to concatenate the broken string
// 3) your are done.
}
else if ([enumPrefix isEqualToString:@"ExampleNonExplicitType"]) {
enumList = @" \
ExampleNonExplicitTypeNEItemName1, \
ExampleNonExplicitTypeNEItemName2, \
ExampleNonExplicitTypeNEItemName3 \
";
}
else if ([enumPrefix isEqualToString:@"ExampleExplicitAssignsType"]) {
enumList = @" \
ExampleExplicitAssignsTypeEAItemName1 = 1, \
ExampleExplicitAssignsTypeEAItemName2 = 2, \
ExampleExplicitAssignsTypeEAItemName3 = 4 \
";
}
else if ([enumPrefix isEqualToString:@"[Duplicate and Add Your Enum Name Here #1"]) {
// Instructions:
// 1) duplicate this else block and add as many enums as you like
// 2) Paste your list, including carraige returns
// 3) add a back slash at the end of each line to continue/concatenate the broken string
enumList = @" \
[Replace only this line: Paste your Enum Definition List Here] \
";
}
// parse it
int implicitIndex = 0;
NSString* itemKey = nil;
NSString* itemValue = nil;
NSArray* enumArray = [enumList componentsSeparatedByString:@","];
NSMutableDictionary* enumDict = [[[NSMutableDictionary alloc] initWithCapacity:enumArray.count] autorelease];
for (NSString* itemPair in enumArray) {
NSArray* itemPairArray = [itemPair componentsSeparatedByString:@"="];
itemValue = [[itemPairArray objectAtIndex:0] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
itemKey = [NSString stringWithFormat:@"%d", implicitIndex];
if (itemPairArray.count > 1)
itemKey = [[itemPairArray lastObject] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
[enumDict setValue:itemValue forKey:itemKey];
implicitIndex++;
}
// return value with or without prefix
NSString* withPrefix = [enumDict valueForKey:[NSString stringWithFormat:@"%d", enumItem]];
NSString* withoutPrefix = [withPrefix stringByReplacingOccurrencesOfString:enumPrefix withString:@""];
NSString* outValue = (0 ? withPrefix : withoutPrefix);
if (0) NSLog(@"enum:%@ item:%d retVal:%@ dict:%@", enumPrefix, enumItem, outValue, enumDict);
return outValue;
}
以下是示例声明:
typedef enum _type1 {
ExampleNonExplicitTypeNEItemName1,
ExampleNonExplicitTypeNEItemName2,
ExampleNonExplicitTypeNEItemName3
} ExampleNonExplicitType;
typedef enum _type2 {
ExampleExplicitAssignsTypeEAItemName1 = 1,
ExampleExplicitAssignsTypeEAItemName2 = 2,
ExampleExplicitAssignsTypeEAItemName3 = 4
} ExampleExplicitAssignsType;
以下是一个示例电话:
NSLog(@"EXAMPLE: type1:%@ type2:%@ ", [self enumItemNameForPrefix:@"ExampleNonExplicitType" item:ExampleNonExplicitTypeNEItemName2], [self enumItemNameForPrefix:@"ExampleExplicitAssignsType" item:ExampleExplicitAssignsTypeEAItemName3]);
享受! ; - )
答案 9 :(得分:2)
你可以使用X宏 - 它们非常适合这种情况。
<强>优势强> 1.实际枚举值和字符串值之间的关系在一个地方。 2.您可以稍后在代码中使用常规切换语句。
<强>损害强> 1.初始设置代码有点迟钝,并使用有趣的宏。
代码
#define X(a, b, c) a b,
enum ZZObjectType {
ZZOBJECTTYPE_TABLE
};
typedef NSUInteger TPObjectType;
#undef X
#define XXOBJECTTYPE_TABLE \
X(ZZObjectTypeZero, = 0, "ZZObjectTypeZero") \
X(ZZObjectTypeOne, = 1, "ZZObjectTypeOne") \
X(ZZObjectTypeTwo, = 2, "ZZObjectTypeTwo") \
X(ZZObjectTypeThree, = 3, "ZZObjectTypeThree") \
+ (NSString*)nameForObjectType:(ZZObjectType)objectType {
#define X(a, b, c) @c, [NSNumber numberWithInteger:a],
NSDictionary *returnValue = [NSDictionary dictionaryWithObjectsAndKeys:ZZOBJECTTYPE_TABLE nil];
#undef X
return [returnValue objectForKey:[NSNumber numberWithInteger:objectType]];
}
+ (ZZObjectType)objectTypeForName:(NSString *)objectTypeString {
#define X(a, b, c) [NSNumber numberWithInteger:a], @c,
NSDictionary *dictionary = [NSDictionary dictionaryWithObjectsAndKeys:ZZOBJECTSOURCE_TABLE nil];
#undef X
NSUInteger value = [(NSNumber *)[dictionary objectForKey:objectTypeString] intValue];
return (ZZObjectType)value;
}
现在你可以做到:
NSString *someString = @"ZZObjectTypeTwo"
ZZObjectType objectType = [[XXObject objectTypeForName:someString] intValue];
switch (objectType) {
case ZZObjectTypeZero:
//
break;
case ZZObjectTypeOne:
//
break;
case ZZObjectTypeTwo:
//
break;
}
这种模式自1960年以来一直存在(不开玩笑!):http://en.wikipedia.org/wiki/X_Macro
答案 10 :(得分:2)
如果您需要在Objective-C编写的Legacy项目中使用Swift代码,下面是一个对Objective-C友好的Enum Struct示例。
示例:强>
contentType.filename。 toString()
返回&#34;文件名&#34;
contentType.filename。 rawValue
返回Int Value,1 (因为它是struct上的第二项)
-(NSInteger)getNumberOfLinesInLabelOrTextView:(id)obj
{
NSInteger lineCount = 0;
if([obj isKindOfClass:[UILabel class]])
{
UILabel *label = (UILabel *)obj;
CGSize requiredSize = [label.text boundingRectWithSize:CGSizeMake(CGRectGetWidth(label.frame), CGFLOAT_MAX) options:NSStringDrawingUsesLineFragmentOrigin attributes:@{NSFontAttributeName:label.font} context:nil].size;
int charSize = label.font.leading;
// now listen , you need to set the text or label with only 1
// then nslog(@"%d",charSize);
// then change the line int charSize = label.font.leading; into
// int charSize = the printed value in case of 1 line
int rHeight = requiredSize.height;
lineCount = rHeight/charSize;
}
else if ([obj isKindOfClass:[UITextView class]])
{
UITextView *textView = (UITextView *)obj;
lineCount = textView.contentSize.height / textView.font.leading;
}
return lineCount;
}
答案 11 :(得分:2)
这是一个老问题,但如果你有一个不连续的枚举,请使用字典文字而不是数组:
typedef enum {
value1 = 0,
value2 = 1,
value3 = 2,
// beyond value3
value1000 = 1000,
value1001
} MyType;
#define NSStringFromMyType( value ) \
( \
@{ \
@( value1 ) : @"value1", \
@( value2 ) : @"value2", \
@( value3 ) : @"value3", \
@( value1000 ) : @"value1000", \
@( value1001 ) : @"value1001", \
} \
[ @( value ) ] \
)
答案 12 :(得分:1)
假设要求是枚举语言列表。
将此添加到.h文件
typedef NS_ENUM(NSInteger, AvailableLanguage) {
ENGLISH,
GERMAN,
CHINENSE
};
现在,在.m文件中,只需创建一个类似的数组,
// Try to use the same naming convention throughout.
// That is, adding ToString after NS_ENUM name;
NSString* const AvailableLanguageToString[] = {
[ENGLISH] = @"English",
[GERMAN] = @"German",
[CHINESE] = @"Chinese"
};
就这样。现在,您可以轻松地使用枚举,并使用数组为枚举获取字符串。例如,
- (void) setPreferredLanguage:(AvailableLanguage)language {
// this will get the NSString* for the language.
self.preferredLanguage = AvailableLanguageToString[language];
}
因此,此模式取决于公认的NS_ENUM命名约定和配套的ToString数组。尝试完全遵循这个约定,它将变得很自然。
答案 13 :(得分:0)
这类似于&#34; X&#34;宏按照像素。 感谢http://en.wikipedia.org/wiki/X_Macro
的链接在宏中生成的代码可能很棘手且难以调试。 相反,生成一个由&#34; normal&#34;使用的表。码。 我发现许多人反对让宏生成代码, 并且可能是&#34; X Macros&#34;技术的一个原因。如上所述 在wiki中没有被广泛采用。
通过生成表格,您仍然只需要编辑一个地点来扩展列表, 因为你不能逐步完成&#34;调试器中的表,这将删除 许多人反对埋藏在宏中的多行代码。
//------------------------------------------------------------------------------
// enum to string example
#define FOR_EACH_GENDER(tbd) \
tbd(GENDER_MALE) \
tbd(GENDER_FEMALE) \
tbd(GENDER_INTERSEX) \
#define ONE_GENDER_ENUM(name) name,
enum
{
FOR_EACH_GENDER(ONE_GENDER_ENUM)
MAX_GENDER
};
#define ONE_GENDER(name) #name,
static const char *enumGENDER_TO_STRING[] =
{
FOR_EACH_GENDER(ONE_GENDER)
};
// access string name with enumGENDER_TO_STRING[value]
// or, to be safe converting from a untrustworthy caller
static const char *enumGenderToString(unsigned int value)
{
if (value < MAX_GENDER)
{
return enumGENDER_TO_STRING[value];
}
return NULL;
}
static void printAllGenders(void)
{
for (int ii = 0; ii < MAX_GENDER; ii++)
{
printf("%d) gender %s\n", ii, enumGENDER_TO_STRING[ii]);
}
}
//------------------------------------------------------------------------------
// you can assign an arbitrary value and/or information to each enum,
#define FOR_EACH_PERSON(tbd) \
tbd(2, PERSON_FRED, "Fred", "Weasley", GENDER_MALE, 12) \
tbd(4, PERSON_GEORGE, "George", "Weasley", GENDER_MALE, 12) \
tbd(6, PERSON_HARRY, "Harry", "Potter", GENDER_MALE, 10) \
tbd(8, PERSON_HERMIONE, "Hermione", "Granger", GENDER_FEMALE, 10) \
#define ONE_PERSON_ENUM(value, ename, first, last, gender, age) ename = value,
enum
{
FOR_EACH_PERSON(ONE_PERSON_ENUM)
};
typedef struct PersonInfoRec
{
int value;
const char *ename;
const char *first;
const char *last;
int gender;
int age;
} PersonInfo;
#define ONE_PERSON_INFO(value, ename, first, last, gender, age) \
{ ename, #ename, first, last, gender, age },
static const PersonInfo personInfo[] =
{
FOR_EACH_PERSON(ONE_PERSON_INFO)
{ 0, NULL, NULL, NULL, 0, 0 }
};
// note: if the enum values are not sequential, you need another way to lookup
// the information besides personInfo[ENUM_NAME]
static void printAllPersons(void)
{
for (int ii = 0; ; ii++)
{
const PersonInfo *pPI = &personInfo[ii];
if (!pPI->ename)
{
break;
}
printf("%d) enum %-15s %8s %-8s %13s %2d\n",
pPI->value, pPI->ename, pPI->first, pPI->last,
enumGenderToString(pPI->gender), pPI->age);
}
}
答案 14 :(得分:0)
一个宏:
#define stringWithLiteral(literal) @#literal
枚举:
typedef NS_ENUM(NSInteger, EnumType) {
EnumType0,
EnumType1,
EnumType2
};
数组:
static NSString * const EnumTypeNames[] = {
stringWithLiteral(EnumType0),
stringWithLiteral(EnumType1),
stringWithLiteral(EnumType2)
};
使用:
EnumType enumType = ...;
NSString *enumName = EnumTypeNames[enumType];
====编辑====
将以下代码复制到您的项目中并运行。
#define stringWithLiteral(literal) @#literal
typedef NS_ENUM(NSInteger, EnumType) {
EnumType0,
EnumType1,
EnumType2
};
static NSString * const EnumTypeNames[] = {
stringWithLiteral(EnumType0),
stringWithLiteral(EnumType1),
stringWithLiteral(EnumType2)
};
- (void)test {
EnumType enumType = EnumType1;
NSString *enumName = EnumTypeNames[enumType];
NSLog(@"enumName: %@", enumName);
}
答案 15 :(得分:0)
Here is working code https://github.com/ndpiparava/ObjcEnumString
//1st Approach
#define enumString(arg) (@""#arg)
//2nd Approach
+(NSString *)secondApproach_convertEnumToString:(StudentProgressReport)status {
char *str = calloc(sizeof(kgood)+1, sizeof(char));
int goodsASInteger = NSSwapInt((unsigned int)kgood);
memcpy(str, (const void*)&goodsASInteger, sizeof(goodsASInteger));
NSLog(@"%s", str);
NSString *enumString = [NSString stringWithUTF8String:str];
free(str);
return enumString;
}
//Third Approcah to enum to string
NSString *const kNitin = @"Nitin";
NSString *const kSara = @"Sara";
typedef NS_ENUM(NSUInteger, Name) {
NameNitin,
NameSara,
};
+ (NSString *)thirdApproach_convertEnumToString :(Name)weekday {
__strong NSString **pointer = (NSString **)&kNitin;
pointer +=weekday;
return *pointer;
}