Question

我想使用Jersey（https://eclipse-ee4j.github.io/jersey/）以编程方式与此API服务进行对话

这是Spring中的Rest Controller实现：

@PostMapping(
      value = "/api/my-endpoint",
      consumes = MediaType.MULTIPART_MIXED_VALUE)
  public void enrichInvoice(@RequestPart("metadata") Map<String, Object> request,
      @RequestPart("human") MultipartFile humanFile) {
    log.info(String.format("received request:%n%s", request));
  }

我的客户端实现将是这样

...
     final Client client = ClientBuilder.newClient(new ClientConfig()
          .register(MultiPartFeature.class)
          .register(JacksonFeature.class)
      );

      final FileDataBodyPart filePart = new FileDataBodyPart("human",myFile()));

      final BodyPart metadata = new BodyPart().entity(voBuilder.generateMetadata());

      final MultiPart multiPartEntity = new MultiPart();
      multiPartEntity.bodyPart(metadata, MediaType.APPLICATION_JSON_TYPE);
      multiPartEntity.bodyPart(filePart);

      final WebTarget target = client
          .target("http://localhost:8080/api/my-endpoint");
      final Entity<MultiPart> entity = Entity
          .entity(multiPartEntity, multiPartEntity.getMediaType());
      log.info(entity.toString());
      final Response response = target
          .request()
          .post(entity);
      log.info(String.format("%s", response.readEntity(String.class)));
      response.close();
...

但是我一直收到此错误：

Resolved [org.springframework.web.multipart.support.MissingServletRequestPartException: Required request part 'metadata' is not present]

这是因为元数据部分必须命名为“元数据”。我找不到使用BodyPart命名的方法。我也尝试过使用FormDataBodyPart来构建元数据

FormDataBodyPart metadataBodyPart = new FormDataBodyPart("metadata", metadata,
          MediaType.APPLICATION_JSON_TYPE);

但结果相同。

您能帮我弄清楚bodyPart定义中缺少什么吗？

谢谢

编辑：这是从我的客户端实现中发送的http请求

Content-Type: multipart/mixed;boundary=Boundary_1_1972899462_1597045386454
User-Agent: Jersey/2.29 (HttpUrlConnection 11.0.8)
MIME-Version: 1.0
Host: localhost:8080
Accept: text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2
Connection: keep-alive
Content-Length: 765

--Boundary_1_1972899462_1597045386454
Content-Type: application/json

{"value":"key"}
--Boundary_1_1972899462_1597045386454
Content-Type: application/octet-stream
Content-Disposition: form-data; filename="file.zip"; modification-date="Wed, 05 Aug 2020 16:52:52 GMT"; size=0; name="human"


--Boundary_1_1972899462_1597045386454--
]

Answer 1

即使不是最佳选择，解决方案是将元数据视为文本文件

final Path tempFile = Files.createTempFile("prefix", "suffix");
File fileMetadata = Files.write(tempFile.toAbsolutePath(), JsonUtils.toString(metadata).getBytes());

final FileDataBodyPart metadataBodyPart = new FileDataBodyPart(
          "metadata",
          fileMetadata,
          MediaType.APPLICATION_JSON_TYPE);

final FileDataBodyPart human = new FileDataBodyPart("human", new File(humanReadableFile.getFileKey()));

try (final MultiPart multiPartEntity = new MultiPart()) {
        multiPartEntity.bodyPart(metadataBodyPart);
        multiPartEntity.bodyPart(human);

    final Response response = client
        .target("http://localhost:8080/api/my-endpoint")
        .request()
        .post(Entity.entity(multiPartEntity, multiPartEntity.getMediaType()));
    log.debug(String.valueOf(response.getStatus()));
    log.debug(response.readEntity(String.class));
}

通过这种方式，请求主体必须按照控制器实现的要求来命名为“元数据”和“人”的部分，并且仍保持多部分/混合内容类型。

通过Jersey客户端发送多部分/混合请求

1 个答案: