我正在尝试模拟对boto3的一些调用,并且看起来模拟函数正在返回正确的值,并且看起来如果我更改断言,那么它不再匹配断言中传递的内容,因为输入参数失败不匹配,但是如果我使它们匹配,则断言将失败:
E AssertionError: assert None
E + where None = <bound method wrap_assert_called_with of <MagicMock name='get_item' id='139668501580240'>>(TableName='TEST_TABLE', Key={'ServiceName': {'S': 'Site'}})
E + where <bound method wrap_assert_called_with of <MagicMock name='get_item' id='139668501580240'>> = <MagicMock name='get_item' id='139668501580240'>.assert_called_with
E + where <MagicMock name='get_item' id='139668501580240'> = <botocore.client.DynamoDB object at 0x7f071b8251f0>.get_item
E + where <botocore.client.DynamoDB object at 0x7f071b8251f0> = site_dao.ddb_client
dynamo数据库对象是一个全局变量。
ddb_client = boto3.client("dynamodb")
def query_ddb():
"""Query dynamo DB for the current strategy.
Returns:
strategy (str): The latest strategy from dynamo DB.
"""
response = None
try:
ddb_table = os.environ["DDB_DA_STRATEGY"]
response = ddb_client.get_item(
TableName=ddb_table, Key={"ServiceName": {"S": "Site"}}
)
except Exception as exception:
LOGGER.error(exception)
raise ServerException("The server was unable to process your request.", [])
return response.get("Item").get("Strategy").get("S")
我的单元测试如下:
def test_data_access_context_strategy_ddb(mocker):
object_key = {
"ServiceName": {"S": "Site"}
}
table_name = "TEST_TABLE"
expected_response = "SqlServer"
os_env = {
"DDB_DA_STRATEGY": table_name,
}
ddb_response = {
"Item": {
"Strategy": {
"S": expected_response
}
}
}
mocker.patch.dict(os.environ, os_env)
mocker.patch.object(site_dao.ddb_client, "get_item")
site_dao.ddb_client.get_item.return_value = ddb_response
data_access_context = site_dao.DataAccessContext()
response = data_access_context.query_ddb()
assert response == expected_response
assert site_dao.ddb_client.get_item.assert_called_with(TableName=table_name, Key=object_key)
如果我更改了assert_called_with
的期望值,我将无法解决问题,例如:
assert site_dao.ddb_client.get_item.assert_called_with(TableName="TT", Key=object_key)
测试失败:
E AssertionError: expected call not found.
E Expected: get_item(TableName='TT', Key={'ServiceName': {'S': 'Site'}})
E Actual: get_item(TableName='TEST_TABLE', Key={'ServiceName': {'S': 'Site'}})
E
E pytest introspection follows:
E
E Kwargs:
E assert {'Key': {'Ser... 'TEST_TABLE'} == {'Key': {'Ser...leName': 'TT'}
E Omitting 1 identical items, use -vv to show
E Differing items:
E {'TableName': 'TEST_TABLE'} != {'TableName': 'TT'}
E Use -v to get the full diff
因此,当预期输入和实际输入不同时,它就会因此失败,但是,当它们相同并且测试应该通过时,它就会失败,因为就好像从未调用过该函数一样。
答案 0 :(得分:3)
您在此行上有两个断言:
assert site_dao.ddb_client.get_item.assert_called_with(TableName=table_name, Key=object_key)
第一个断言是assert_called_with
,听起来像是您想要的。然后在行的开头有另一个断言:assert ...
,它在assert_called_with
函数的返回值上断言。断言通过时,该返回值为null
。因此,整行结果为assert null
。
tl; dr请勿重复使用assert
。