当有多对多的关系时,你必须显式创建中间连接表吗?如何向迁移添加外键?我有一个用户模型和一个书模型。我安装了foreigner。到目前为止,这是我的代码。有人可以告诉我如何从这里开始吗?
USER
class User < ActiveRecord::Base
has_and_belongs_to_many :books
# Include default devise modules. Others available are:
# :token_authenticatable, :lockable, :timeoutable and :activatable
devise :database_authenticatable, :registerable,
:recoverable, :rememberable, :trackable, :validatable
# Setup accessible (or protected) attributes for your model
attr_accessible :email, :password, :password_confirmation
end
书模型
class Book < ActiveRecord::Base
has_and_belongs_to_many :users
end
移民书籍
class CreateBooks < ActiveRecord::Migration
def self.up
create_table :books do |t|
t.string :title
t.string :author
t.timestamps
end
end
def self.down
drop_table :books
end
end
移民用户
class DeviseCreateUsers < ActiveRecord::Migration
def self.up
create_table(:users) do |t|
t.database_authenticatable :null => false
t.recoverable
t.rememberable
t.trackable
# t.lockable :lock_strategy => :failed_attempts, :unlock_strategy => :both
t.timestamps
end
add_index :users, :email, :unique => true
add_index :users, :reset_password_token, :unique => true
# add_index :users, :unlock_token, :unique => true
end
def self.down
drop_table :users
end
end
答案 0 :(得分:2)
是的,你需要一个联接表。使用has_and_belongs_to_many
时的约定是将连接表命名为model1_model2
。因此,在这种情况下,您的迁移需要看起来像这样:
create_table :books_users, :id => false do |t|
t.integer :user_id, :null => false
t.integer :book_id, :null => false
end
请注意:id =&gt; false部分,这是为了确保连接表不会自动获取自己的id。