Question

我的JSON响应如下所示。我想删除大括号（周围带有**），以便获取卡密钥中的值。我可以这样做吗，还是会弄乱整个词典？如果是这样，我想在大括号前（在**之前）分配键值。

希望有人可以帮助我解决这个问题，如果您能给我有关python字典的进一步说明，我会很高兴！

[
    **{**
        "board": {
            "id": "5f2106f0a188d073ebf3604b",
            "name": "TrAPI_test",
            "shortLink": "OIeEN1vG"
        },
        "card": {
            "id": "5f236a13a64ee90e7ef95341",
            "idShort": 3,
            "name": "task3",
            "shortLink": "WNHiHWxh"
        },
        "idMember": "5e1d96663a14c86d44d0edc4",
        "member": {
            "id": "5e1d96663a14c86d44d0edc4",
            "name": "Zorigt"
        }
    **}**,
    {
        "board": {
            "id": "5f2106f0a188d073ebf3604b",
            "name": "TrAPI_test",
            "shortLink": "OIeEN1vG"
        },
        "card": {
            "id": "5f236a13a64ee90e7ef95341",
            "idShort": 3,
            "name": "task3",
            "shortLink": "WNHiHWxh"
        },
        "list": {
            "id": "5f22161e221bea80b90d96ad",
            "name": "SprintTask"
        }
    }

]

Answer 1

我之所以能够得到它，是因为它一直是多个字典的列表：））

{
    "0": {
        "board": {
            "id": "5f2106f0a188d073ebf3604b",
            "name": "TrAPI_test",
            "shortLink": "OIeEN1vG"
        },
        "card": {
            "id": "5f236a13a64ee90e7ef95341",
            "idShort": 3,
            "name": "task3",
            "shortLink": "WNHiHWxh"
        },
        "idMember": "5e1d96663a14c86d44d0edc4",
        "member": {
            "id": "5e1d96663a14c86d44d0edc4",
            "name": "Zorigt"
        }
    },
    "1": {
        "board": {
            "id": "5f2106f0a188d073ebf3604b",
            "name": "TrAPI_test",
            "shortLink": "OIeEN1vG"
        },
        "card": {
            "id": "5f236a13a64ee90e7ef95341",
            "idShort": 3,
            "name": "task3",
            "shortLink": "WNHiHWxh"
        },
        "list": {
            "id": "5f22161e221bea80b90d96ad",
            "name": "SprintTask"
        }
    }
}

使用此

Dict_convert= {}
for idx, val in enumerate(List): 
    Dict_convert[idx] = val

如何从字典中删除/删除大括号/大括号？

1 个答案: