Question

编辑：

错误：

06-12 19:25:55.880: ERROR/AndroidRuntime(226): Uncaught handler: thread main exiting due to uncaught exception
06-12 19:25:55.910: ERROR/AndroidRuntime(226): java.lang.NullPointerException
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at com.laytproducts.songmaster.mainAct$1.onClick(mainAct.java:124)
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at android.view.View.performClick(View.java:2364)
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at android.view.View.onTouchEvent(View.java:4179)
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at android.widget.TextView.onTouchEvent(TextView.java:6541)
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at android.view.View.dispatchTouchEvent(View.java:3709)
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:884)
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:884)
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:884)
06-12 19:25:55.910: ERROR/AndroidRuntime(226):     at android.view.ViewGroup.dispatchTouchEvent(ViewGroup.java:884)
....

代码：

rawHtml = getHtml(baseSite + rSearched); //get the raw html of page
if(rawHtml == null || rawHtml.length() < 1){//checks if it really contains anything
    Toast.makeText(getApplicationContext(), "Error: Got No Result", Toast.LENGTH_SHORT).show();
    Log.e("RawHtml Error:1", "Nothing In rawHtml String");
} else {
    for(int i = 1; i < 7; i++){
        String html = parseHtml(rawHtml,i);
        if(html == null || html.length() < 1){
            results[i-1] = "Result not found:Please try different lyrics";
        } else {
            results[i-1] = parseHtml(rawHtml,i); //error here
        }
    }
}

parseHtml：

public String parseHtml(String html,int num){
    String parsed = "";
    String artistParse = "";
    String songParse = "";
    //String fullHtmlParse = "#NUMBER#. &nbsp;<span>This Charming Man</span> &nbsp; by Smiths</a>";//Reference
    if(num != 0 && num <= 6){
        songParse = StringUtils.substringBetween(html,num+". &nbsp;<span>","</span>");
        artistParse = StringUtils.substringBetween(html,num+". &nbsp;<span>"+songParse+"</span> &nbsp; by ","</a>");
    } else {
        Toast.makeText(getApplicationContext(),
                "Error: Number is wrong in parseHtml, Please Try Again.", Toast.LENGTH_SHORT).show();
        Log.e("ParsedHtml Error:1","Error: Number in parseHtml is invalid: " + num);
        return "";
    }
    parsed = songParse + ":" + artistParse;
    return parsed;
}

getHtml：

public String getHtml(String url){
    String html = "";
    String baseHtml = "";
    String table = "";
    try {
        baseHtml = new StringReader(url).toString();
    } catch (Exception e) {
        Toast.makeText(getApplicationContext(), "Error getting HtmlDoc, Please Try Again.", Toast.LENGTH_SHORT).show();
        e.printStackTrace();
        return "";
    }
    if(baseHtml == null || baseHtml.length() < 1){
        Toast.makeText(getApplicationContext(), "Error getting HtmlDoc, Please Try Again.", Toast.LENGTH_SHORT).show();
        Log.e("BaseHtml Error:1","Error: Nothing in baseHtml[method getHtml(String url)]");
        return "";
    } else {
        //table = StringUtils.substringBetween(baseHtml,"<!-- EyesLyrics.com search results -->","</table>");
    }
    html = baseHtml;
    return html;
}

希望这就是你所需要的。

Answer 1

要显示Toast，您需要调用show() - 方法。像这样：

Toast.makeText(getApplicationContext(), "Error getting HtmlDoc, Please Try Again.", Toast.LENGTH_SHORT).show();

有关详细信息，请参阅here。

if(rawHtml == "" || rawHtml == null){[...]}

我猜rawHtml - 对象是一个字符串？在这种情况下，如果你想检查这个String是否为空，你既不会使用equals("") - 方法，也不会检查字符串的长度：

if (rawHtml.length < 1)

此外，如果您需要检查字符串是否为null，则应首先执行此操作，因为检查长度（例如）会导致NullPointerException。

关于您的代码

if(rawHtml == null ...

测试rawHtml是否为空是不必要的，因为在getHtml - 方法中，您将其作为空字符串创建。永远不会是null。

return "";

您在parseHtml和getHtml - 方法中返回一个空字符串。我宁愿返回null，然后检查返回的值是否为null。你可以放弃一个具有相同效果的条件。

results[i-1] = "...";

计算应该用括号括起来，如下所示：

results[(i-1)] = "...";

你的错误aperas就在这一行：

results[i-1] = parseHtml(rawHtml,i);

由于我无法看到您是否初始化results - 对象，我想这是您的问题。在您可以访问（写入或读取）此数组中的元素之前，需要初始化该数组。

这就是你如何做到这一点，猜测你的数组是一个字符串数组：

String[] results = new String[NumberOfElements];

我希望这能解决你的问题。

应用程序不抓取HTML

1 个答案:

关于您的代码