Question

我希望循环继续进行，即使在第一次迭代中生成异常。该怎么做？

mydict = {}
wl = ["test", "test1", "test2"]
    
try:
  for i in wl:
   a = mydict['sdf']
   print(i)
            
except:
       # I want the loop to continue and print all elements of list, instead of exiting it after exception
       # exception will occur because mydict doesn't have 'sdf' key
    pass

Answer 1

您可以使用dict.get()。如果密钥不存在，它将返回None。您也可以在dict.get(key, default_value)

中指定默认值

for i in wl:
    a = mydict.get('sdf')
    print(i)

Answer 2

我能建议的最好方法是将try移入循环，如下所示：

mydict = {}
wl = ["test", "test1", "test2"]
for i in wl:
    try:
        a = mydict['sdf']
        print(i)

    except:
        continue

Answer 3

这是我为您解决问题的方法
希望它为您服务

mydict = {}
wl = ["test", "test1", "test2"]

for i in wl:
    try:
        a = mydict['sdf']
    except:
        pass
    print(i)

发生异常时继续循环

3 个答案: