Question

例如，我想更新数组中任务的第一个对象。请记住，任务数组属于另一个数组。

例如{“ firstName”：“多行”， “ lastName”：“多行”}

我尝试了以下操作，但是无法正常工作：

   const index = req.params.id;
     const { firstName, lastName, taskIndex } = req.body;
      
      const foundTask = await Task.findById(index); //to Find index from parent array
      const foundTaskItem = await foundTask.tasks[taskIndex]; // to find the object to update
    
// Need correct below
      Task.update(
        { _id: ObjectId(index), tasks: foundTaskItem },
        { $push: { }
      ); // I feel this is wrong

 [ 
        {
            "tasks": [
                {
                    "firstName": "multiple lines",
                    "lastName": "multiple lines"
                },
                {
                    "firstName": "multiple lines2",
                    "lastName": "multiple lines2"
                }
            ],
            "_id": "5f22e48a97097d24e416bdf9",
            "additional": "testing",
            "date": "2020-07-30T15:17:30.236Z",
            "__v": 0
        },
        {
            "tasks": [
                {
                    "firstName": "Michael ",
                    "lastName": "Jordan"
                },
                {
                    "firstName": "Scottie",
                    "lastName": "Pippen"
                }
            ],
            "_id": "5f248750e2e0b01180c49283",
            "additional": "Chicago Bulls",
            "date": "2020-07-31T21:04:16.519Z",
            "__v": 0
        }
    ]

     [![enter image description here][1]][1]


  [1]: https://i.stack.imgur.com/ChDcJ.png

Answer 1

您可以使用以下更新来更新任务：

Task.findOneAndUpdate(
      { _id: ObjectId(index), tasks.firstName: "multiple lines2" },
      { $set: { "tasks.$.firstName": "updated multiple lines2" } },
      { new: true, sort: { _id: -1 } }).exec()
      .then(result => {})
      .catch(error => {
        console.log(error)
      })

Answer 2

我是个白痴。我通过在行const foundTaskItem = await foundTask.tasks[taskIndex].firstName中添加.firstName来解决它；并使用foundTaskItem作为“ tasks.firstName”的值：。

const index = req.params.id;
  const { firstName, lastName, taskIndex, additional } = req.body;
  console.log(taskIndex);

  const foundTask = await Task.findById(index);
  const foundTaskItem = await foundTask.tasks[taskIndex].firstName;
  
  Task.findOneAndUpdate(
    { _id: index, "tasks.firstName": foundTaskItem },
    { $set: { "tasks.$.firstName": firstName } },
    { new: true, sort: { _id: -1 } }
  )

更新猫鼬数组中的元素

2 个答案: