在线程中启动烧瓶

时间:2020-07-31 21:33:49

标签: python multithreading flask

我尝试将一个方法称为线程,然后在StartServer方法正在后台运行时调用另一个方法,但是当执行self.Thread.run()时,代码将卡住。有任何想法吗 ?我尝试将启动服务器放在另一个类的外部函数中,但仍然存在该问题。

import time
import webview
import threading
from flask import Flask

class Windows:

    def __init__(self, EntryPoint = "index.html"):

        self.EntryPointContent = self.ReadPage(EntryPoint)

        self.Thread = threading.Thread(target = self.StartServer)
        self.Thread.daemon = True
        self.Thread.run()
        
        self.ShowWindows()

    def StartServer(self):

        app = Flask(__name__)
        app.debug = False
        app.reloader = False

        @app.route("/")
        def root():
            return self.EntryPointContent

        app.run()


    def ReadPage(self, FileName):

        File = open(FileName, "r")
        return File.read()


    def ShowWindows(self):

        webview.create_window("Hey !", "http://localhost:5000")
        webview.start()

app = Windows(EntryPoint="page.html")

2 个答案:

答案 0 :(得分:1)

我猜是这样

app.reloader = False

没有按照您的期望去做。相反,尝试

app.run(use_reloader=False)

答案 1 :(得分:1)

致电Thread.run()而不是Thread.start()。运行将只在当前线程上调用您的StartServer方法。下面是一个简短的示例,您可以尝试一下。

import threading
from time import sleep


def l(msg):
    while True:
        print(msg)
        sleep(1)


thread = threading.Thread(target=lambda: l('foo'))
thread.start() # swap with thread.run()

l('bar')