Question

我有两个对象数组（array1，array2）。我正在尝试返回最终数组（如下所示），它消除了array2中的重复项，但没有消除array1中的重复项。我将array1作为优先级。

array1 =[
    { phone: "07485454", name: "John" },
    { phone: "054554", name: "Ryan" },
]

array2 =[
    { phone: "2144564", name: "John" },
    { phone: "286456", name: "Mike" },
]

这是我最终想要的东西。仅从array2删除重复项。最终数组：

[
   { phone: "07485454", name: "John" },
   { phone: "054554", name: "Ryan" },
   { phone: "286456", name: "Mike" },
]

这是我尝试过的事情：

for(let i = 0; i < array1.length; i++) {
    let name = array1[i].name;
  for(let a = 0; i < array2.length; a++) {
      let newname = array2[a].name;
      if(name !== newname) {
       array1.push(
         {
           phone: array2[a].phone,
           name: array2[a].name
         });
      }
    
    console.log(array1);
  }
  
}

这是我得到的错误。

"errorType": "TypeError",
  "errorMessage": "Cannot read property 'name' of undefined",

Answer 1

您已接近解决方案，可以创建一个Set来包含array1元素的名称，并将array1元素推入result数组；随后将array2中未包含名称的set元素添加到result数组中：

function removeDuplicates(array1, array2) {
    const result = [];
    const set = new Set();

    for (const elem of array1) {

        result.push(elem);
        set.add(elem.name);
    } 

    for (const elem of array2) {

        if (!set.has(elem.name)) {

            result.push(elem);
        }
    }

    return result;
    
}

const array1 =[
    { phone: "07485454", name: "John" },
    { phone: "054554", name: "Ryan" }
];

const array2 =[
    { phone: "2144564", name: "John" },
    { phone: "286456", name: "Mike" }
];

console.log(JSON.stringify(removeDuplicates(array1, array2)));

Answer 2

您在内部for循环条件中犯了错字 a

更改array1的长度将导致无限循环

每次，当 if（name！== newname）为真时，在array1中插入新对象将导致更改array1的长度。

let array1 =[ { phone: "07485454", name: "John" }, { phone: "054554", name: "Ryan" }, ] let array2 =[ { phone: "2144564", name: "John" }, { phone: "286456", name: "Mike" }, ] let result = array2.reduce((accumulator, currentItem) =>{ let index = accumulator.findIndex(item => item.name === currentItem.name); if(index === -1){ accumulator.push(currentItem); } return accumulator; },array1); console.log(result);

比较两个对象数组并返回最终结果

2 个答案: