Question

我一直在解决这个问题已有一段时间了，目前我正试图将我的php脚本转换为PDO，但是当通过isset（）运行时，$ _POST总是给我null。我在android中的代码可以与其他脚本正常工作，但是当我将每个项目上的$ _POST更改为$ _REQUEST时，该脚本仅在邮递员中有效，并且链接看起来也有所不同。还值得一提的是，onResponse和onFailure不会接收/打印任何消息。

邮递员网址

http://123.456.7.89/Database/register.php?username=asdfasdf&password=lj4ioidfoislkjsf&email=jalenpauloiudf&tece=true&profilePicPath=aksdfjlakjdsfl&tokenId=as89gwbeg98sd

当前网址

http://123.456.7.89/Database/register.php

脚本

<?php

$servername = "localhost";
$dbUsername = "root";
$dbPassword = "password";
$dbname = "Database";

try {
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $dbUsername, $dbPassword);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    
    $username = $_POST['username'];
    $password = $_POST['password'];
    $email = $_POST['email'];
    $termsOfService = $_POST['termsOfService'];
    $profilePicPath = $_POST['profilePicPath'];
    $tokenId = $_POST['tokenId'];
    $userId = uniqId();

    //converting data
    $termsOfService = $termsOfService ? 'true' : 'false';

    //Username check
    $emailForQuery = "%" . $_POST['email'] . "%";
    $userIdForQuery = "%" . $userId . "%";
    $usernameCheckQuery = $conn->prepare("SELECT email, userId FROM users WHERE email LIKE ? OR userId LIKE ? LIMIT 1");
    $usernameCheckQuery->execute([$emailForQuery, $userIdForQuery]); 
    $usernameCheckQuery->fetch();

    if ($usernameCheckQuery->rowCount() == 0) {//username doesnt exist
        $usernameCheckQuery->closeCursor();

        $hashedPassword = password_hash($password, PASSWORD_DEFAULT);
        $query = $conn->prepare("INSERT INTO users(userId, username, password, email, termsOfService, profilePicPath, tokenId) 
            VALUES(?, ?, ?, ?, ?, ?, ?)");
        $query->execute([$userId, $username, $hashedPassword, $email, $termsOfService, $profilePicPath, $tokenId]);
        $query->closeCursor();

        header('Content-type:application/json;charset=utf-8');
        $resArray = ['success' => true, 'userId' => $userId];
        echo json_encode($resArray);

    } else { //username exists
        $usernameCheckQuery->closeCursor();
        connectionError("username already exists");
    }
        
} catch(PDOException $e) {    
    connectionError();
}

function connectionError($message = "database connection error") { //sending response
    header('Content-type:application/json;charset=utf-8');
    $resArray = ['success' => false, 'message' => $message];
    echo json_encode($resArray);
    $conn = null;
}

？>

Android帖子数据

    @FormUrlEncoded
@POST("register.php")
fun signUpUser(@Field("username") username: String,
               @Field("password") password: String,
               @Field("email") email: String,
               @Field("termsOfService") termsOfService: Boolean,
               @Field("profilePicPath") profilePicPath: String,
               @Field("tokenId") tokenId: String): Call<ResponseLoginOrSignUp>

我的猜测是它与网址有关，但随后响应仍未发送。

如果需要任何其他代码，请告诉我，请加上添加。

答案!!! 这是我的结论，我的域名安全性不佳，需要将ssl添加到我的托管域以及自定义域中。对于ssl，我使用cloudflare来寻找免费ssl的任何人，因为花了我一段时间才找到合适的网站。还将android studio中显示的网址中的http切换为https

Answer 1

在android清单中使用 android：usesCleartextTraffic =“ true”

Answer 2

首先，尝试将Http更改为https

然后我建议使用android volley发布请求

https://developer.android.com/training/volley[Android齐射示例] 1

$ _POST请求适用于邮递员，但不适用于android app

2 个答案: