from pulp import *
import numpy as np
import pandas as pd
X = [1, 2]
Y = ['0-5', '5-10', '10-15']
A = [[1, 2, 3],
[4, 5, 6]]
test = makeDict((X, Y), A)
假设我有这个。我想找到x \ in X和y \ in Y的A(x,y + 1)-A(x,y)的值,并将其放入列表中。我怎样才能做到这一点?我可以打印A(x,y)。我这样做了,但是没有用。
B = []
for i in range(len(A)):
for j in range(len(X)):
x = A[i][j+1] - A[i][j]
y = B.append(x)
print(y)
test