我写了一个相当简单的类的文档,但我觉得它不够清楚。我应该改变什么吗?
/**
Pointer class that wraps resources loaded through the ResourceManager.
The manager is notified to increase or decrease the reference count of
a resource, as a ResourcePtr gets copied, created, or deleted.
If a resource has a reference count of zero, the ResourceManager will
delete it. The reference count of a resource is the same as the number
of ResourcePtr objects that reference it.
\see ResourceManager
*/
template<class T>
class ResourcePtr
{
public:
/**
Default constructor. Creates an empty ResourcePtr that does not
reference any resource.
*/
ResourcePtr();
/**
Copy constructor. Create a copy and increase the reference count
of the resource referenced by the ResourcePtr being copied, if any.
*/
ResourcePtr(const ResourcePtr<T>& other);
/**
Destroy the ResourcePtr and release one reference to the resource
it points to, if any. The resource is deleted if there are no more
ResourcePtr objects that reference it.
*/
~ResourcePtr();
/**
Access the resource inside the ResourcePtr.
\return Pointer to the resource or null if ResourcePtr is empty.
*/
const T* get() const;
/**
Arrow operator. Provided for convenience to access members of
the resource class directly, without having to first call get().
An assertion failure occurs if the ResourcePtr is empty.
*/
const T* operator->() const;
/**
Assignment operator. Release the resource currently pointing to,
if any. Copy the data from the other ResourcePtr and increase
the reference count of the resource it points to, if any.
*/
ResourcePtr<T>& operator=(const ResourcePtr<T>& other);
private:
friend class ResourceManager<T>;
typename std::list<typename
ResourceManager<T>::ResourceWrapper*>::iterator iter_;
};
答案 0 :(得分:3)
您错过了这些评论都是不必要的事实,只会使代码更难以阅读和理解。它们相当于:
i++; // increment i