$str = preg_replace("'\(look: (.{1,80})\)'Ui",
"(look: <a href=\"dict.php?process=word&q=\\1\">\\1</a>)",$str);
我想编码网址,但我该怎么做呢?
我可以在preg_replace中使用urlencode()函数吗?
$str = preg_replace("'\(look: (.{1,80})\)'Ui",
"(look: <a href=\"dict.php?process=word&q=\\1\">\\1</a>)",$str);
你对preg_replace中的url编码有什么想法吗?
答案 0 :(得分:8)
您可以使用preg_replace_callback
,它允许您通过直接运行代码来生成替换字符串:
$str = preg_replace_callback(
"'\(look: (.{1,80})\)'Ui",
create_function(
'$matches',
'return \'(look: <a href="dict.php?process=word&q='.urlencode($matches[1]).'">'.
$matches[1].'</a>)\';'
),
$str);
如果你使用PHP&gt; = 5.3,你可以减少上面的痛苦:
$str = preg_replace_callback(
"'\(look: (.{1,80})\)'Ui",
function($matches) {
return "(look: <a href=\"dict.php?process=word&q=".urlencode($matches[1])."\">".
$matches[1]."</a>)";
},
$str);