我有这样的信号:
virtual_daily_created = django.dispatch.Signal(providing_args=['min_date', 'max_date', 'train_id'])
从这样的视图调用它:
signal = virtual_daily_created.send_robust(self.__class__, min_date=start_ts,
max_date=end_ts,
train_id=train_id)
并且接收者在这样定义的类中:
class BigQueryData:
def __init__(self):
some_code
def set_query(self, table: bigquery.TableReference, train_id: str, min_date: datetime,
max_date: datetime,**kwargs) -> str:
do_thing
def set_table(self, type: str) -> bigquery.TableReference:
do_thing
@receiver(virtual_daily_created)
def get_gga_data(self, min_date: datetime, max_date: datetime, train_id: str, **kwargs):
do_thing
最后,在我的包含BigQueryData类的应用中,我具有一个app.py文件:
from django.apps import AppConfig
from django.dispatch import receiver
class ShiftsConfig(AppConfig):
name = 'shifts'
def ready(self):
from api.v1.virtual_daily_report import VirtualDailyReportList
from reports.signals import virtual_daily_created
virtual_daily_created.connect(receiver, sender=VirtualDailyReportList)
问题是当收到信号时出现此错误:
get_gga_data()缺少1个必需的位置参数:“ self”
所以我试图这样改变信号:
virtual_daily_created = django.dispatch.Signal(providing_args=['self', 'min_date', 'max_date', 'train_id'])
并这样称呼它:
signal = virtual_daily_created.send_robust(self.__class__, self=BigQueryData(),
min_date=start_ts,
max_date=end_ts,
train_id=train_id)
但是当我收到信号时,我得到了这个错误:
send_robust()为参数'self'获得了多个值
是否有可能从以self作为第一个arg的方法接收信号?
谢谢:)
答案 0 :(得分:1)
将其标记为静态方法或类方法,以便能够在不需要self参数的情况下调用它。
@receiver(virtual_daily_created)
@staticmethod
def get_gga_data(min_date: datetime, max_date: datetime, train_id: str, **kwargs):
do_thing