Question

我有必须用理由踢用户的脚本。

语法：

$ kick @用户原因

但是当我键入：

$ kick sometext nexttext

我在控制台中出错：

TypeError：无法读取未定义的属性“踢”

和机器人停止...

如何编辑此脚本，以便在输入不正确的值后不会关闭机器人并弹出错误，并且机器人会将消息发送到通道。 “值不正确”？

脚本：

const discord = require('discord.js');
const client = new discord.Client;
const prefix = "$";
 client.on('message', function(message) {
const args = message.content.slice(prefix.length).trim().split(/ +/g);

const command = args.shift().toLowerCase();

if(command === "kick") {

 let member = message.mentions.members.first();
 let reason = args.slice(1).join(" ");
  member.kick(reason);
  message.delete();
  client.channels.cache.get('737341022782357566').send("User <@" + member.id + "> with id " + member.id + " has been kicked by <@" + message.author.id + "> with reason " + reason)  

}})
client.login('token');

Answer 1

在javascript中执行可能会崩溃的代码，您可以使用语句

try {
//code to test
} catch(err) {
//code if it crash
}

Answer 2

添加一个if (member)来测试是否有提及。

在其他情况下，您可以发送“错误命令”消息

您还应该仅在消息以您的前缀开头的情况下触发漫游器

const discord = require('discord.js');
const client = new discord.Client;
const prefix = "$";

client.on('message', function(message) {
  if (!message.content.startsWith(prefix)) { return } 
  //this line prevents the bot to execute every message
  const args = message.content.slice(prefix.length).trim().split(/ +/g);

  const command = args.shift().toLowerCase();

  if(command === "kick") {

    let member = message.mentions.members.first();
    let reason = args.slice(1).join(" ");
    if (member) { // add this
      member.kick(reason);
      client.channels.cache.get('737341022782357566').send(`User ${member.user} with id: ${member.id} has been kicked by ${message.author} with reason: ${reason}`); 
    } else {
      message.reply("invalid parameters for $kick")
    }

    message.delete();
  }
})

client.login('token');

如何使机器人在出错后不停止？ Discord.js

2 个答案: