Question

我正在从API获取数据，我想根据问题状态过滤阵列。以下代码可以正常工作，但是有没有写这个好的方法？

let issuesToUse = this.state.issues;

if(this.state.issueState.status === 'closed'){
  issuesToUse = this.state.issues.filter(issue => {
    return issue.state === 'closed';
  })
} else {
  issuesToUse = this.state.issues.filter(issue => {
    return issue.state === 'open';
  })
}

Answer 1

issuesToUse = this.state.issues.filter(issue => issue.state === this.state.issueState.status)

Answer 2

如果还有其他状态，则需要事先检查该状态以进行过滤。

find . -name 'dir2-*' -exec mkdir {}/dir3-1 \;

Answer 3

您可以尝试以下示例

let targetState = this.state.issueState.status;
let issuesToUse = this.state.issues.filter(
  ({ state }) => state === targetState
);

请参见

Destructuring assignment

根据条件过滤阵列的最佳方法

3 个答案: