Question

我想从basicData中给我的id作为我整个Company对象的ObjectID。这怎么可能？我已经尝试过：_id: { type: mongoose.Types.ObjectId, ref: "Company" }，但是不起作用... 你有解决办法吗？

我的代码：

import mongoose, { Schema, Document, Collection, mongo } from "mongoose";

const CompanySchema = new Schema(
  {
    basicData: {
      _id: { type: mongoose.Types.ObjectId, auto: true }, // that id I want to give her the complete ObjectID of Company
      tasks: {
        type: [],
        validate: {
          validator: (arr: any) => {
            return arr.length > 0;
          },
          message: "You must provide more than 0 tasks.",
        },
        title: { type: String, required: [true, "title is required"] },
      },
      partner: {
        type: Number,
        required: [true, "partner is required"],
        min: 0,
        max: 10,
      },
      riskFactor: {
        type: Number,
        required: [true, "riskFactor is required"],
        min: 0,
        max: 10,
      },
      name: { type: String, required: [true, "name is required"] },
    },
  },
  {
    versionKey: false,
    typePojoToMixed: false,
  }
);
const Company = mongoose.model("Company", CompanySchema);
export default Company;

Answer 1

您可以在companySchema文件中创建一个basicSchema，插入时将自动获得_id：

// Company.js

const BasicDataSchema = new Schema({
      tasks: {
        type: [],
        validate: {
          validator: (arr: any) => {
            return arr.length > 0;
          },
          message: "You must provide more than 0 tasks.",
        },
        title: { type: String, required: [true, "title is required"] },
      },
      partner: {
        type: Number,
        required: [true, "partner is required"],
        min: 0,
        max: 10,
      },
      riskFactor: {
        type: Number,
        required: [true, "riskFactor is required"],
        min: 0,
        max: 10,
      },
      name: { type: String, required: [true, "name is required"] }
});

const CompanySchema = new Schema({
 basicData: BasicDataSchema,
 ...
});

我如何给我的ID猫鼬ObjectID？整个对象？

1 个答案: