Question

此代码在游戏开始时在某个区域内的地图上生成了100只鸡，但是玩家已经收集了全部100只鸡，没有剩余的要收集，所以id想知道如何重新生成另外100只鸡，说一次剩余数量已减少到10，因此玩家将有连续数量的鸡可以收集，希望这是有道理的，在此先感谢。 jp

local newChicken = game.ServerStorage:FindFirstChild("ChickenOnePart")

local TopLeftCorner = Vector3.new(-187.64, 20.679, 106.2)
local BottomRightCorner = Vector3.new(201.12, 20.679, -241.45)
local numberOfChickens = 100
local counter = 0

local singleTonRandom = Random.new(tick())

local function GetRandom(Min,Max)
return singleTonRandom:NextNumber(Min,Max)
end


while counter < numberOfChickens  do
local chicken = newChicken:Clone()
chicken.Anchored = true
chicken.Parent = game.Workspace
chicken.Name = "Chicken"
chicken.Position = Vector3.new(
    GetRandom(TopLeftCorner.X,BottomRightCorner.X),
    4,
    GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
)
counter = counter + 1

end

此代码每次玩家触摸鸡时将计数器加1。我可以从这里获得当前的鸡只数量吗？

if hitPart.Name == "Chicken" then
    event:FireServer(hitPart)
    local currentcount = playerGUI.ChickenGui.ChickenCounter.Text
    playerGUI.ChickenGui.ChickenCounter.Text = currentcount + 1
    hitPart:Destroy()
    debounce = true
    wait(0.1)
    debounce  = false
end
end)

并且此代码用于更新领导者。

local event = Instance.new("RemoteEvent")
event.Name = "CurrencyAdd"
event.Parent = game.ReplicatedStorage

event.OnServerEvent:Connect(function(plr,part)
local currency = plr.leaderstats.Chickens
currency.Value = currency.Value + 1
end)


game.Players.PlayerAdded:Connect(function(plr)
local ls = Instance.new("Folder")
ls.Name = "leaderstats"
local m = Instance.new("IntValue",ls)
m.Name = "Chickens"
ls.Parent = plr

local cash = Instance.new("IntValue",ls)
cash.Name = "Cash"
end)

@Piglet谢谢，我有点理解这是什么意思？

local newChicken = game.ServerStorage:FindFirstChild("ChickenOnePart")

local TopLeftCorner = Vector3.new(-187.64, 20.679, 106.2)
local BottomRightCorner = Vector3.new(201.12, 20.679, -241.45)
local numberOfChickens = 100
local counter = 0

local singleTonRandom = Random.new(tick())

local function GetRandom(Min,Max)
return singleTonRandom:NextNumber(Min,Max)
end

for counter = 1, numberOfChickens do
local chicken = newChicken:Clone()
chicken.Anchored = true
chicken.Parent = game.Workspace
chicken.Name = "Chicken"
chicken.Position = Vector3.new(
    GetRandom(TopLeftCorner.X,BottomRightCorner.X),
    4,
    GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
)
counter = counter + 1
end

function AddChicken(num)
for count = 10, num do
local chicken = newChicken:Clone()
chicken.Anchored = true
chicken.Parent = game.Workspace
chicken.Name = "Chicken"
chicken.Position = Vector3.new(
  GetRandom(TopLeftCorner.X,BottomRightCorner.X),
  4,
  GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
)
end        
end
AddChicken(90)

对不起，我只是学习全部

Answer 1

基本上，只需将while循环放入其自己的函数中，然后每当鸡的数量低于一定阈值时就调用该函数，就像调用GetRandom来将鸡放置在适当的位置一样：

function GenerateChickens()
    while counter < numberOfChickens  do
        local chicken = newChicken:Clone()
        chicken.Anchored = true
        chicken.Parent = game.Workspace
        chicken.Name = "Chicken"
        chicken.Position = Vector3.new(
            GetRandom(TopLeftCorner.X,BottomRightCorner.X),
            4,
            GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
        )
        counter = counter + 1
    end
end

我不知道您将如何获得当前的鸡数量，但这应该是一个好的开始。

Answer 2

因为这样的循环很常见，所以形式比以下更短：

local counter = 0
while counter < numberOfChickens do
  -- ...
  counter = counter + 1
end

这可以使用数字for循环来写

for counter = 1, numberOfChickens do
  -- ...
end

在只剩10只鸡的情况下再增加100只鸡，因为您建议您给110只鸡。因此，如果要在地图上添加100只鸡，则应添加90张。

为此，每当取出一只鸡时，都应检查鸡的数量。条件一成立，您就应该调用添加一定数量的鸡肉的函数。

function AddChicken(num)
  for count = 1, num do
    local chicken = newChicken:Clone()
    chicken.Anchored = true
    chicken.Parent = game.Workspace
    chicken.Name = "Chicken"
    chicken.Position = Vector3.new(
      GetRandom(TopLeftCorner.X,BottomRightCorner.X),
      4,
      GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
    )
  end        
end

只需确保该功能在newChicken的范围内

想知道游戏中的循环循环如何工作

2 个答案: