Question

我希望每当用户打开应用程序时运行一项服务，然后只要每隔1分钟安装一次该应用程序便使其运行。该服务将通过调用API来检查是否有新订单，如果有则将显示通知。

我已经进行了一些研究，发现JobIntentService和Broadcast Reciever是解决问题所需要的，但我无法将它们组合在一起以使其正常工作。如果有人可以提供详细的解决方案，我将不胜感激。我还想知道是否有比我的问题更好的东西？下面是我设法编写的代码。

后台服务

public class BackgroundService extends JobIntentService {

    private static final String TAG = BackgroundService.class.getName();

    private static final int JOB_ID = 1;
    private NotificationManager notificationManager;

    public static void enqueueWork(Context context, Intent intent) {
        enqueueWork(context, BackgroundService.class, JOB_ID, intent);
    }

    @Override
    public void onCreate() {
        super.onCreate();
        Log.d(TAG, getClass().getSimpleName() + "#onCreate");
        notificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
    }

    @Override
    public void onDestroy() {
        super.onDestroy();
        Log.d(TAG, "Running in background!");
        sendBroadcast(new Intent(getApplicationContext(), BackgroundService.class));
    }

    @Override
    protected void onHandleWork(@NonNull Intent intent) {
        Log.d(TAG, getClass().getSimpleName() + "#onHandleWork!");

        APIInterface service = RetrofitClientInstance.getRetrofitInstance().create(APIInterface.class);
        Call<List<OrdersModel>> call = service.getAllOrders(Services.CONSUMER_KEY,Services.CONSUMER_SECRET);
        call.enqueue(new Callback<List<OrdersModel>>() {
            @Override
            public void onResponse(@NonNull Call<List<OrdersModel>> call,@NonNull Response<List<OrdersModel>> response) {
                if (response.body() != null) {
                    for (OrdersModel orders : response.body()){
                        if (orders.getStatus().equals("processing")){
                            sendNotification("#" + orders.getNumber());
                        }
                    }
                }
            }

            @Override
            public void onFailure(@NonNull Call<List<OrdersModel>> call,@NonNull Throwable t) {
                Log.d(TAG, getClass().getSimpleName() + "Network Error!");
            }
        });
    }

    private void sendNotification(String title) {

        Uri defaultSound = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);

        Intent intent = new Intent(this, GetOrdersActivity.class);
        intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);
        PendingIntent pendingIntent = PendingIntent.getActivity(this, 0, intent, 0);

        Notification.Builder notificationBuilder = new Notification.Builder(this)
                .setSmallIcon(R.mipmap.ic_launcher_round)
                .setContentTitle(title)
                .setAutoCancel(true)
                .setSound(defaultSound)
                .setContentText("New Order")
                .setContentIntent(pendingIntent)
                .setWhen(System.currentTimeMillis())
                .setPriority(Notification.PRIORITY_HIGH)
                .setCategory(Notification.CATEGORY_MESSAGE);

        notificationManager.notify(0, notificationBuilder.build());

        Log.d("GoParty", "Notification sent ----- ");
    }
}

BroadcastReciever

public class NotificationReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {

        Intent notificationIntent = new Intent(context, BackgroundService.class);
        BackgroundService.enqueueWork(context, notificationIntent);
    }
}

Answer 1

那不是应该的工作方式。移动设备上的应用必须保留电池寿命。轮询效果不佳。您想要的是一个推送通知，服务器正在其中发挥作用。例如，您可以使用Firebase Cloud Messaging来实现。

看看：https://firebase.google.com/docs/cloud-messaging/android/client?authuser=0

服务器负责知道何时有新订单可用，并且可以在恰好适当的时机采取行动，向客户应用发送推送通知。

每1分钟显示一次通知Android

1 个答案: