我遇到一个奇怪的问题,我花了好几天才缩小范围。基本上,我有一个基于Spring引导版本2.1.10.RELEASE的Jhipster项目,其中包含4个微服务。我们对其中的两个感兴趣:Gateway和Corehub。 在网关中,我有一个有角度的应用程序,该应用程序执行到/ services / corehub / api / someendpoint的POST程序,该程序曾经可以正常运行,但现在由于出现不同的错误消息而失败了,但是我经常看到的是
{
"type": "https://www.jhipster.tech/problem/problem-with-message",
"title": "Method Not Allowed",
"status": 405,
"detail": "Request method 'POST' not supported",
"path": "/services/ambientcorehub/api/trips",
"message": "error.http.405"
}
我最终查看了跟踪内部服务微服务的注册表的痕迹,发现发生此错误时,我再也找不到痕迹中的corehub了。因此看来corehub微服务尚未注册。
此服务的另一个GIT分支没有此问题,因此我在这两个分支之间进行了比较,并删除了更改,直到可以缩小问题的范围。 因此,在corehub中,我有一个基于此mq-jms-spring实现的JMS侦听器。 Maven依赖关系如下:
<dependency>
<groupId>com.ibm.mq</groupId>
<artifactId>mq-jms-spring-boot-starter</artifactId>
<version>2.2.7</version>
</dependency>
我注释掉了我的JmsListener类及其关联的JmsContext(以获取对主题的访问),并仅保留定义对服务器的访问的配置属性以及端口,通道,主题名称等。
如果我评论以上Maven依赖项,则我的服务将再次起作用。 如果我保持maven依赖关系(仅使用配置),则我的corehub微服务未在注册表中注册,并且无法再从网关(因此也无法从Angular UI)访问。
需要注意的重要一点是,我目前遇到一些网络问题,使我无法访问JMS服务器。 因此,我相信由于无法访问JMS服务器而导致的此IBM库引发的异常将使微服务的注册向Spring Boot注册表中断。
以下是在corehub控制台中反复出现的痕迹:
2020-07-22 08:21:45.316 WARN 7964 --- [nfoReplicator-0] o.s.boot.actuate.jms.JmsHealthIndicator : JMS health check failed
com.ibm.msg.client.jms.DetailedIllegalStateException: JMSWMQ0018: Failed to connect to queue manager '' with connection mode 'Client' and host name '172.31.14.1(9010)'.
at com.ibm.msg.client.wmq.common.internal.Reason.reasonToException(Reason.java:489)
at com.ibm.msg.client.wmq.common.internal.Reason.createException(Reason.java:215)
at com.ibm.msg.client.wmq.internal.WMQConnection.<init>(WMQConnection.java:448)
at com.ibm.msg.client.wmq.factories.WMQConnectionFactory.createV7ProviderConnection(WMQConnectionFactory.java:8475)
at com.ibm.msg.client.wmq.factories.WMQConnectionFactory.createProviderConnection(WMQConnectionFactory.java:7815)
at com.ibm.msg.client.jms.admin.JmsConnectionFactoryImpl._createConnection(JmsConnectionFactoryImpl.java:303)
at com.ibm.msg.client.jms.admin.JmsConnectionFactoryImpl.createConnection(JmsConnectionFactoryImpl.java:236)
at com.ibm.mq.jms.MQConnectionFactory.createCommonConnection(MQConnectionFactory.java:6005)
at com.ibm.mq.jms.MQConnectionFactory.createConnection(MQConnectionFactory.java:6030)
at org.springframework.jms.connection.SingleConnectionFactory.doCreateConnection(SingleConnectionFactory.java:409)
at org.springframework.jms.connection.SingleConnectionFactory.initConnection(SingleConnectionFactory.java:349)
at org.springframework.jms.connection.SingleConnectionFactory.getConnection(SingleConnectionFactory.java:327)
at org.springframework.jms.connection.SingleConnectionFactory.createConnection(SingleConnectionFactory.java:242)
at org.springframework.boot.actuate.jms.JmsHealthIndicator.doHealthCheck(JmsHealthIndicator.java:52)
at org.springframework.boot.actuate.health.AbstractHealthIndicator.health(AbstractHealthIndicator.java:82)
at org.springframework.boot.actuate.health.CompositeHealthIndicator.health(CompositeHealthIndicator.java:95)
at org.springframework.cloud.netflix.eureka.EurekaHealthCheckHandler.getHealthStatus(EurekaHealthCheckHandler.java:110)
at org.springframework.cloud.netflix.eureka.EurekaHealthCheckHandler.getStatus(EurekaHealthCheckHandler.java:106)
at com.netflix.discovery.DiscoveryClient.refreshInstanceInfo(DiscoveryClient.java:1406)
at com.netflix.discovery.InstanceInfoReplicator.run(InstanceInfoReplicator.java:117)
at java.base/java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:515)
at java.base/java.util.concurrent.FutureTask.run(FutureTask.java:264)
at java.base/java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:304)
at java.base/java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1128)
at java.base/java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:628)
at java.base/java.lang.Thread.run(Thread.java:834)
Caused by: com.ibm.mq.MQException: JMSCMQ0001: IBM MQ call failed with compcode '2' ('MQCC_FAILED') reason '2538' ('MQRC_HOST_NOT_AVAILABLE').
at com.ibm.msg.client.wmq.common.internal.Reason.createException(Reason.java:203)
... 24 common frames omitted
Caused by: com.ibm.mq.jmqi.JmqiException: CC=2;RC=2538;AMQ9204: Connection to host '172.31.14.1(9010)' rejected. [1=com.ibm.mq.jmqi.JmqiException[CC=2;RC=2538;AMQ9204: Connection to host '/172.31.14.1:9010' rejected. [1=java.net.ConnectException[Connection timed out: connect],3=/172.31.14.1:9010,4=TCP,5=Socket.connect]],3=172.31.14.1(9010),5=RemoteTCPConnection.bindAndConnectSocket]
at com.ibm.mq.jmqi.remote.api.RemoteFAP$Connector.jmqiConnect(RemoteFAP.java:13558)
at com.ibm.mq.jmqi.remote.api.RemoteFAP.jmqiConnect(RemoteFAP.java:1426)
at com.ibm.mq.jmqi.remote.api.RemoteFAP.jmqiConnect(RemoteFAP.java:1385)
at com.ibm.mq.ese.jmqi.InterceptedJmqiImpl.jmqiConnect(InterceptedJmqiImpl.java:377)
at com.ibm.mq.ese.jmqi.ESEJMQI.jmqiConnect(ESEJMQI.java:562)
at com.ibm.msg.client.wmq.internal.WMQConnection.<init>(WMQConnection.java:381)
... 23 common frames omitted
Caused by: com.ibm.mq.jmqi.JmqiException: CC=2;RC=2538;AMQ9204: Connection to host '/172.31.14.1:9010' rejected. [1=java.net.ConnectException[Connection timed out: connect],3=/172.31.14.1:9010,4=TCP,5=Socket.connect]
at com.ibm.mq.jmqi.remote.impl.RemoteTCPConnection.bindAndConnectSocket(RemoteTCPConnection.java:901)
at com.ibm.mq.jmqi.remote.impl.RemoteTCPConnection.protocolConnect(RemoteTCPConnection.java:1381)
at com.ibm.mq.jmqi.remote.impl.RemoteConnection.connect(RemoteConnection.java:976)
at com.ibm.mq.jmqi.remote.impl.RemoteConnectionSpecification.getNewConnection(RemoteConnectionSpecification.java:553)
at com.ibm.mq.jmqi.remote.impl.RemoteConnectionSpecification.getSessionFromNewConnection(RemoteConnectionSpecification.java:233)
at com.ibm.mq.jmqi.remote.impl.RemoteConnectionSpecification.getSession(RemoteConnectionSpecification.java:141)
at com.ibm.mq.jmqi.remote.impl.RemoteConnectionPool.getSession(RemoteConnectionPool.java:127)
at com.ibm.mq.jmqi.remote.api.RemoteFAP$Connector.jmqiConnect(RemoteFAP.java:13302)
... 28 common frames omitted
Caused by: java.net.ConnectException: Connection timed out: connect
at java.base/java.net.PlainSocketImpl.connect0(Native Method)
at java.base/java.net.PlainSocketImpl.socketConnect(PlainSocketImpl.java:101)
at java.base/java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:399)
at java.base/java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:242)
at java.base/java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:224)
at java.base/java.net.SocksSocketImpl.connect(SocksSocketImpl.java:403)
at java.base/java.net.Socket.connect(Socket.java:609)
at java.base/java.net.Socket.connect(Socket.java:558)
at com.ibm.mq.jmqi.remote.impl.RemoteTCPConnection$4.run(RemoteTCPConnection.java:1022)
at com.ibm.mq.jmqi.remote.impl.RemoteTCPConnection$4.run(RemoteTCPConnection.java:1014)
at java.base/java.security.AccessController.doPrivileged(Native Method)
at com.ibm.mq.jmqi.remote.impl.RemoteTCPConnection.connectSocket(RemoteTCPConnection.java:1014)
at com.ibm.mq.jmqi.remote.impl.RemoteTCPConnection.bindAndConnectSocket(RemoteTCPConnection.java:805)
... 35 common frames omitted
以下是一些版本号:
这是我在application.yml中的配置:
spring:
jms:
# Used for JMS Message reception.
isPubSubDomain: false
application:
oag:
# This can be a queue or a topic (if subdomain is defined)
# In case of a topic, sub domain must be set to public.
queueName: "BRIDGE.XXX.TO.YYY.TST"
isTopic: false
ibm:
mq:
queueManager:
channel: XXX_GWT11.BT1
connName: 172.31.14.1(9010)
user: xxxx
password:
是否有可能捕获此异常,以避免破坏常规的Spring Boot注册机制? 由于无法访问JMS服务器,我无法承受关闭群集的费用。
此外,我在IBM MQ端here上打开了此消息,有人建议我停止JMS运行状况指示器。因此,我将以下属性设置为无效:
management:
endpoint:
jms:
# Prevent Unreachable JMS Server from unregistering corehub from the registry, leading to unreachable microservice from the Gateway
enabled: false
相应的文档为here
任何帮助将不胜感激。 谢谢 克里斯托夫(Christophe)
答案 0 :(得分:2)
如果您不希望在JMS关闭时将应用程序视为不正常,建议您禁用JMS运行状况指示器。由于您使用过management.endpoint.jms.enabled
,因此它对您不起作用。正确使用的属性是management.health.jms.enabled
:
management:
health:
jms:
enabled: false