Question

我有一个简单的函数，可以确定字符串是否包含子字符串。

def scoring_names(string, substring1, substring2, substring3):
    """Simple function to calculate the substrings in a string"""
    score_list=[]
    sub1 = string.count(substring1)
    score_list.append(sub1)
    sub2 = string.count(substring2)
    score_list.append(sub2)
    sub3 = string.count(substring3)
    score_list.append(sub3)
    #print(score_list)
    return sum(score_list)

我也有一个数据框：

import pandas as pd 
# data  
data = [['James', 'Bond','Crazy','james_bond_fox'],
        ['John','Smith','Blackhand','davinchi_84'], 
        ['Jose','Romero', 'Bear','jose.gamez']]

# Create the pandas DataFrame 
df = pd.DataFrame(data, columns = ['Str_1', 'Str_2', 'Str_3', 'String'])

在数据框上应用该功能时-我看到以下错误：

TypeError: list indices must be integers or slices, not str
AttributeError: 'RangeIndex' object has no attribute 'levels'

有人可以建议我如何解决问题吗？

Answer 1

为我工作。

df.apply(lambda x: scoring_names(x['String'],x['Str_1'],x['Str_2'],x['Str_3']),axis=1)

尽管如此，您可能需要进行一些区分大小写的调整，例如像这样：

def scoring_names(string, substring1, substring2, substring3):
    """Simple function to calculate the substrings in a string"""
    string = string.lower()
    substring1 = substring1.lower()
    substring2 = substring2.lower()
    substring3 = substring3.lower()
    
    score_list=[]
    sub1 = string.count(substring1)
    score_list.append(sub1)
    sub2 = string.count(substring2)
    score_list.append(sub2)
    sub3 = string.count(substring3)
    score_list.append(sub3)
    #print(score_list)
    return sum(score_list)

将功能应用于数据框

1 个答案: