我想拥有以下的PHP代码。
假设我有一个图片网址,例如http://www.google.co.in/intl/en_com/images/srpr/logo1w.png
如果我运行一个脚本,该图像将被复制并放在我的服务器上具有777权限的文件夹中。
有可能吗?如果是的话,你能指点一下吗?
谢谢,
伊恩
答案 0 :(得分:128)
两种方式,如果你使用的是PHP5
copy('http://www.google.co.in/intl/en_com/images/srpr/logo1w.png', '/tmp/file.jpeg');
如果没有,请使用file_get_contents
//Get the file
$content = file_get_contents("http://www.google.co.in/intl/en_com/images/srpr/logo1w.png");
//Store in the filesystem.
$fp = fopen("/location/to/save/image.jpg", "w");
fwrite($fp, $content);
fclose($fp);
答案 1 :(得分:26)
来自Copy images from url to server, delete all images after
function getimg($url) {
$headers[] = 'Accept: image/gif, image/x-bitmap, image/jpeg, image/pjpeg';
$headers[] = 'Connection: Keep-Alive';
$headers[] = 'Content-type: application/x-www-form-urlencoded;charset=UTF-8';
$user_agent = 'php';
$process = curl_init($url);
curl_setopt($process, CURLOPT_HTTPHEADER, $headers);
curl_setopt($process, CURLOPT_HEADER, 0);
curl_setopt($process, CURLOPT_USERAGENT, $user_agent); //check here
curl_setopt($process, CURLOPT_TIMEOUT, 30);
curl_setopt($process, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($process, CURLOPT_FOLLOWLOCATION, 1);
$return = curl_exec($process);
curl_close($process);
return $return;
}
$imgurl = 'http://www.foodtest.ru/images/big_img/sausage_3.jpg';
$imagename= basename($imgurl);
if(file_exists('./tmp/'.$imagename)){continue;}
$image = getimg($imgurl);
file_put_contents('tmp/'.$imagename,$image);
答案 2 :(得分:15)
$url="http://www.google.co.in/intl/en_com/images/srpr/logo1w.png";
$contents=file_get_contents($url);
$save_path="/path/to/the/dir/and/image.jpg";
file_put_contents($save_path,$contents);
您必须将allow_url_fopen
设置为on
答案 3 :(得分:7)
此SO thread将解决您的问题。简而言之:
$url = 'http://www.google.co.in/intl/en_com/images/srpr/logo1w.png';
$img = '/my/folder/my_image.gif';
file_put_contents($img, file_get_contents($url));
答案 4 :(得分:4)
$url = "http://www.example/images/image.gif";
$save_name = "image.gif";
$save_directory = "/var/www/example/downloads/";
if(is_writable($save_directory)) {
file_put_contents($save_directory . $save_name, file_get_contents($url));
} else {
exit("Failed to write to directory "{$save_directory}");
}