Question

如何获得像这样的嵌套pojo结果

object
------object
------object
------------object
------array

这是我从一个忘记的地方得到的，但是它没有代码来实现此结果。

{
  "success": true,
  
  "counter": {
    "pending": 100,
    "rejected": 200,
    "completed": 300,
    "expired": 400,
    "total": 3200
  },
  "pie_statistics": {
    "assigned": 120,
    "opened": 212,
    "in-progress": 100,
    "completed": 320,
    "done": 433,
    "rejected": 111,
    "expired": 332
  },
  
  "bar_months":[
  "jan",
  "feb",
  "mar"
],
  
  "bar_pending":[
    100,
    200,
    300
  ],
  
   "bar_rejected":[
    140,
    220,
    340
  ],
  
  
   "bar_completed":[
    170,
    290,
    310
  ]
  
}

使用这样的代码

<?php 

require "connection.php";

$query =    "SELECT a.kondisi, k.area, COUNT(k.area) AS carea, COUNT(k.nrp) AS cnrp
            FROM tb_absens AS a
            INNER JOIN tb_karyawans AS k 
            ON a.nrp = k.nrp
            WHERE a.kondisi = 'Sehat' 
            GROUP BY k.area";

$data = mysqli_query($conn, $query);
$json_array = array();

while($row = mysqli_fetch_array($data)){
    array_push($json_array, array(
        "success"   =>  true,
        "cnrp"      =>  $row["cnrp"],
        "area"      =>  $row["area"],
        "kondisi"   =>  $row["kondisi"],
    ));
}

echo json_encode($json_array);

我这样的结果

[
{
    "success": true,
    "cnrp": "1",
    "area": "Administrator",
    "kondisi": "Sehat"
},
{
    "success": true,
    "cnrp": "2",
    "area": "AMK CPBP",
    "kondisi": "Sehat"
},..
]

是的，我知道这是一个古老的问题，有许多类似的问题。但是我一点都不知道。感谢您的帮助。谢谢。

Answer 1

如果要将不同的json类型转换为单个json，可以先拆分查询，然后执行每个查询。为了得到这样的嵌套对象结果

"counter": {
    "pending": 100,
    "rejected": 200,
    "completed": 300,
    "expired": 400,
    "total": 3200
  },

尝试执行

while($row = mysqli_fetch_assoc($data)){

    $json_arr['counter'][$row['a']] = $row['b'];
       
}

用于嵌套数组

"bar_months":[
  "jan",
  "feb",
  "mar"
]

使用此

 while($row = mysqli_fetch_assoc($data)){
        $json_arr2['bar_months'][] = $row_area['months'];
 }

并将其合并为单个json您可以使用

echo json_encode(array_merge($json_arr, $json_arr2));

希望它会有所帮助

我如何从php mysql获取嵌套的pojo结果

1 个答案: