Question

import { createSlice, PayloadAction } from '@reduxjs/toolkit';
import { AppInfo } from '../models';

const initialState: AppInfo | null = null;

const appSlice = createSlice({
  name: 'app',
  initialState,
  reducers: {
    selectApp(state, action: PayloadAction<AppInfo>) {
      return action.payload;
    },
  },
});

export const { selectApp } = appSlice.actions;
export default appSlice.reducer;

// models.ts
export type AppInfo = {
  appName: string;
  createDate: string;
  develop: string;
  op: string;
};

我希望在Redux启动时将state.app设为null，但稍后允许用户选择应用程序。但是，我在减速器selectApp上遇到了很长的TypeScript错误。这个错误是什么意思？

(method) selectApp(state: null, action: PayloadAction<AppInfo>): AppInfo
Type '(state: null, action: { payload: AppInfo; type: string; }) => AppInfo' is not assignable to type 'CaseReducer<null, { payload: any; type: string; }> | CaseReducerWithPrepare<null, PayloadAction<any, string, any, any>>'.
Type '(state: null, action: { payload: AppInfo; type: string; }) => AppInfo' is not assignable to type 'CaseReducer<null, { payload: any; type: string; }>'.
Type 'AppInfo' is not assignable to type 'void'.ts(2322)

Answer 1

https://www.reddit.com/r/reduxjs/comments/guns93/nullable_state_best_practice_typescript_redux/

export type AuthState = AppInfo | null;

const initialState = null as AuthState;

我在reddit帖子中找到了答案。似乎null将使打字稿将类型缩小为null而不是AppInfo | null。使用as可以解决问题。

初始状态为null时，为什么createSlice出现错误？

1 个答案: