Question

Bonjour

这是我的应用程序的组件树：

"use strict";
function createFilter(fn) {
    // Accept all currently filtered elements.
    function acceptNode(node) {
        return NodeFilter.FILTER_ACCEPT;
    }
    if (fn == null)
        fn = acceptNode;
    // Work around Internet Explorer wanting a function instead of an object.
    // IE also *requires* this argument where other browsers don't.
    const safeFilter = fn;
    safeFilter.acceptNode = fn;
    return safeFilter;
}
function createTabbingFilter() {
    // Accept all currently filtered elements.
    function acceptNode(node) {
        if (!node)
            return NodeFilter.FILTER_REJECT;
        if (node.nodeType !== Node.ELEMENT_NODE)
            return NodeFilter.FILTER_REJECT;
        if (window.getComputedStyle(node).display === "none")
            return NodeFilter.FILTER_REJECT;
        // "tabIndex": "0"
        if (!node.hasAttribute("tabIndex"))
            return NodeFilter.FILTER_SKIP;
        let tabIndex = parseInt(node.getAttribute("tabIndex"), 10);
        if (!tabIndex || isNaN(tabIndex) || !isFinite(tabIndex))
            return NodeFilter.FILTER_SKIP;
        // if ((<Element>node).tagName !== "LI") return NodeFilter.FILTER_SKIP;
        return NodeFilter.FILTER_ACCEPT;
    }
    return createFilter(acceptNode);
}
function getNextTab(el) {
    let currentNode;
    // https://developer.mozilla.org/en-US/docs/Web/API/Document/createNodeIterator
    // https://developer.mozilla.org/en-US/docs/Web/API/Document/createTreeWalker
    // let ni = document.createNodeIterator(el, NodeFilter.SHOW_ELEMENT);
    // let ni = document.createTreeWalker(this.m_tree, NodeFilter.SHOW_ELEMENT);
    let ni = document.createTreeWalker(document.documentElement, NodeFilter.SHOW_ELEMENT, createTabbingFilter(), false);
    ni.currentNode = el;
    while (currentNode = ni.nextNode()) {
        return currentNode;
    }
    return el;
}
function getPreviousTab(el) {
    let currentNode;
    let ni = document.createTreeWalker(document.documentElement, NodeFilter.SHOW_ELEMENT, createTabbingFilter(), false);
    ni.currentNode = el;
    while (currentNode = ni.previousNode()) {
        return currentNode;
    }
    return el;
}

所以我想将数据从assetStatus组件发送到组件数据以提供图形。

谢谢

Answer 1

如果组件不相关，则可以使用服务。如果您的组件具有父子关系，则可以使用@Input @Output方式。

对于您的情况，您可以使用一项通用服务。

import { Injectable } from '@angular/core';
import { BehaviorSubject } from 'rxjs';
@Injectable()
export class ShareService  {   
  constructor() { } 
  private paramSource = new BehaviorSubject("");// inside bracket you can send any type
  sharedData = this.paramSource.asObservable();
  setParam(param:string) { this.paramSource.next(param)}    
}

添加到应用模块providers:[ShareService ]中的提供者

在构造函数中设置。

constructor(private shareService: ShareService  ){}

设置为服务

this.shareService.setParam('Sending param');

获得服务

 this.shareService.sharedData.subscribe(data=> { console.log(data); })

将数据从一个组件发送到另一组件

1 个答案: