Question

我的数据库列如下所示：

  `matDes1` varchar(255) DEFAULT NULL,
  `matCost1` int(255) DEFAULT NULL,
  `matDes2` varchar(255) DEFAULT NULL,
  `matCost2` int(255) DEFAULT NULL,
  `matDes3` varchar(255) DEFAULT NULL,
  `matCost3` int(255) DEFAULT NULL,
  `matDes4` varchar(255) DEFAULT NULL,
  `matCost4` int(255) DEFAULT NULL,
  `matDes5` varchar(255) DEFAULT NULL,
  `matCost5` int(255) DEFAULT NULL,

我有一个动态表，其中包含我的HTML文件中的添加和删除行。

在此表中，我有文本区域和输入内容，每当我开始键入内容时，就会向我显示建议，如果选择一个，则会自动填充其他字段。

在我的文本区域下方输入以下内容：

<textarea id='codeANCILLARY_1' class='codeANCILLARY' name="codeANCILLARY[]"></textarea>

<input type="text" id="mat50ANCILLARY_1" class="mat50ANCILLARY" name="mat50ANCILLARY[]" />

textarea搜索从matDes1到matDes5。所以这里没问题。

问题是选择来填充两个场时，只接受matDes1和matCost1不其余部分。

是否可以使用诸如if语句之类的说法：

if (matDes1 selected) {
show matDes1 with matCost1
} else if (matDes2 selected){
show matDes2 with matCost2
}
and 
so 
on

我真的不知道该怎么办。：（

完整的jQuery和PHP文件是：

$(document).on('keydown', '.codeANCILLARY', function () {

        var id = this.id;
        var splitid = id.split('_');
        var count = splitid[1];

        $('#' + id).autocomplete({
            source: function (request, response) {
                $.ajax({
                    url: "../../MY_PHP_PAGE",
                    type: 'post',
                    dataType: "json",
                    data: {
                        search: request.term,
                        request: 1
                    },
                    success: function (data) {
                        response(data);
                    }
                });
            },
            select: function (event, ui) {
                $(this).val(ui.item.label);
                var id = ui.item.value;

                // AJAX
                $.ajax({
                    url: '../../MY_PHP_PAGE',
                    type: 'post',
                    data: {
                        id: id,
                        request: 2
                    },
                    dataType: 'json',
                    success: function (takesAnyVaribale) {
                        var len = takesAnyVaribale.length;
                        if (len > 0) {
                            var codeANCILLARY = takesAnyVaribale[0]['codeANCILLARY'];
                            var mat50ANCILLARY = takesAnyVaribale[0]['mat50ANCILLARY'];
                            var unitsANCILLARY = takesAnyVaribale[0]['unitsANCILLARY'];
                          
                            $('#codeANCILLARY_' + count).val(codeANCILLARY);
                            $('#mat50ANCILLARY_' + count).val(mat50ANCILLARY);
                            $('#unitsANCILLARY_' + count).val(unitsANCILLARY);
                        }
                    }
                });
                return false;
            }
        });
    });

"MY_PHP_PAGE"

include "config.php";
$request = $_POST['request'];

if ($request == 1) {
    $search = $_POST['search'];
    $query1 = "SELECT * FROM MY_COMPONENTLIST WHERE matDes1 like'%".$search."%'";
    $query2 = "SELECT * FROM MY_COMPONENTLIST WHERE matDes2 like'%".$search."%'";
    $query3 = "SELECT * FROM MY_COMPONENTLIST WHERE matDes3 like'%".$search."%'";
    $query4 = "SELECT * FROM MY_COMPONENTLIST WHERE matDes4 like'%".$search."%'";
    $query5 = "SELECT * FROM MY_COMPONENTLIST WHERE matDes5 like'%".$search."%'";
    $result1 = mysqli_query($con, $query1);
    $result2 = mysqli_query($con, $query2);
    $result3 = mysqli_query($con, $query3);
    $result4 = mysqli_query($con, $query4);
    $result5 = mysqli_query($con, $query5);
    if ($result1 || $result2 || $result3 || $result4 || $result5) {
        while ($row = mysqli_fetch_array($result1)) {
            $response[] = array("value"=>$row['id'],"label"=>$row['matDes1']);
        }
        while ($row = mysqli_fetch_array($result2)) {
            $response[] = array("value"=>$row['id'],"label"=>$row['matDes2']);
        }
        while ($row = mysqli_fetch_array($result3)) {
            $response[] = array("value"=>$row['id'],"label"=>$row['matDes3']);
        }
        while ($row = mysqli_fetch_array($result4)) {
            $response[] = array("value"=>$row['id'],"label"=>$row['matDes4']);
        }
        while ($row = mysqli_fetch_array($result5)) {
            $response[] = array("value"=>$row['id'],"label"=>$row['matDes5']);
        }
    }
    echo json_encode($response);
    exit;
}

if ($request == 2) {
    $id = $_POST['id'];
    $sql = "SELECT * FROM MY_COMPONENTLIST WHERE id=".$id;
    $result = mysqli_query($con, $sql);
    $AncillaryPricing_arr = array();
    while ($row = mysqli_fetch_array($result)) {
        $id = $row['id'];
        $codeANCILLARY = $row['matDes1'];
        $mat50ANCILLARY = $row['matCost1'];
        //***************************
        //***************************
        $codeANCILLARY = $row['matDes2'];        
         $mat50ANCILLARY = $row['matCost2'];
        .and
        .so on 
        .until 5
        //***************************
        //***************************
        $unitsANCILLARY = $row['units'];
        $AncillaryPricing_arr[] = array(
            "id" => $id,
            "codeANCILLARY" => $codeANCILLARY,
            "mat50ANCILLARY" => $mat50ANCILLARY,
            "unitsANCILLARY" => $unitsANCILLARY
        );
    }
    echo json_encode($AncillaryPricing_arr);
    exit;
}

Answer 1

正是出于这个原因，您确实确实需要更好的数据库布局。将matdes和matcost列拆分到一个单独的表中，该表由组件ID链接。然后，您可以拥有任意数量的内容，并且搜索起来要容易得多。而不是所有单独的查询，您将拥有类似的

SELECT * FROM MY_COMPONENTLIST_MAT WHERE matDes like'%".$search."%' and component_id = " . $id

（作为准备好的语句除外），它将找到其中的任何一个。您可以使用JOIN从主要组件列表中获取其余信息。

从PHP / MySQL使用jQuery自动完成功能

1 个答案: