我正在运行一个python程序,以从canada.ca下载选定的CSV文件列表。我拥有所需的所有网址,但不知道如何将其下载到本地目录。我相信我必须使用一个请求,并在循环中写入文件。但是,我对此实在迷失了,谢谢。
en_urls = []
for link in soup.find_all('a'):
if 'EN.csv' in link.get('href', []):
en_urls.append(link.get('href'))
Output
['http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/Positive_Employers_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2015_Positive_Employers_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2016_Positive_Employer_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2017Q1Q2_Positive_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2017Q3_Positive_Employer_Stream_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2018Q1_Positive_Employer_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2018Q2_Positive_Employer_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2017Q4_Positive_Employer_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2018Q3_Positive_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2018Q4_Positive_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/imt-lmi/TFWP_2019Q1_employer_positive_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/imt-lmi/TFWP_2019Q2_employer_positive_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/imt-lmi/TFWP_2019Q3_Positive_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/imt-lmi/TFWP_2019Q4_Positive_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/imt-lmi/TFWP_2020Q1_Positive_EN.csv']
答案 0 :(得分:1)
您可以循环使用urllib.request.urlretrieve()
。
例如:
conversationId
打印:
import urllib.request
lst = ['http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/Positive_Employers_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2015_Positive_Employers_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2016_Positive_Employer_EN.csv',
'http://www.edsc-esdc.gc.ca/ouvert-open/bca-seb/ae-ei/2017Q1Q2_Positive_EN.csv']
for i in lst:
print('Downloading {}..'.format(i))
local_filename, _ = urllib.request.urlretrieve(i, filename=i.split('/')[-1])
print('File saved as {}'.format(local_filename))
答案 1 :(得分:0)
尝试一下:
my_arr.reshape(2234,1)