Question

我正在尝试为移动触摸事件实施Google的“快速”按钮，而我似乎陷入困境。我正在尝试设置它以便我可以链接到快捷按钮，但我似乎无法使我的库结构正确。当我尝试在链接上运行for循环时，最终发生的是fastbutton重新进入。

我确定这只是我设置图书馆的方式。有人可以看看吗？谢谢！

http://code.google.com/mobile/articles/fast_buttons.html

    ;(function() {
/*Construct the FastButton with a reference to the element and click handler.*/
this.FastButton = function(element, handler) {
    console.log('fastbutton init');
    this.element = element;
    this.handler = handler;
    console.log(this);
    element.addEventListener('touchstart', this, false);
    element.addEventListener('click', this, false);
};

/*acts as an event dispatcher*/
this.FastButton.prototype.handleEvent = function(event) {
    console.log(event);
    switch (event.type) {
        case 'touchstart': this.onTouchStart(event); break;
        case 'touchmove': this.onTouchMove(event); break;
        case 'touchend': this.onClick(event); break;
        case 'click': this.onClick(event); break;
    }
};

/*Save a reference to the touchstart coordinate and start listening to touchmove and
 touchend events. Calling stopPropagation guarantees that other behaviors don’t get a
 chance to handle the same click event. This is executed at the beginning of touch.*/
this.FastButton.prototype.onTouchStart = function(event) {
    event.stopPropagation();
    this.element.addEventListener('touchend', this, false);
    document.body.addEventListener('touchmove', this, false);
    this.startX = event.touches[0].clientX;
    this.startY = event.touches[0].clientY;
};

/*When /if touchmove event is invoked, check if the user has dragged past the threshold of 10px.*/
this.FastButton.prototype.onTouchMove = function(event) {
    if (Math.abs(event.touches[0].clientX - this.startX) > 10 ||
            Math.abs(event.touches[0].clientY - this.startY) > 10) {
        this.reset(); //if he did, then cancel the touch event
    }
};

/*Invoke the actual click handler and prevent ghost clicks if this was a touchend event.*/
this.FastButton.prototype.onClick = function(event) {
    event.stopPropagation();
    this.reset();
    this.handler(event);
    if (event.type == 'touchend') {
        console.log('touchend');
        //clickbuster.preventGhostClick(this.startX, this.startY);
    }
};

this.FastButton.prototype.reset = function() {
    this.element.removeEventListener('touchend', this, false);
    document.body.removeEventListener('touchmove', this, false);
};

this.clickbuster = function() {
    console.log('init clickbuster');
}
/*Call preventGhostClick to bust all click events that happen within 25px of
 the provided x, y coordinates in the next 2.5s.*/
this.clickbuster.preventGhostClick = function(x, y) {
clickbuster.coordinates.push(x, y);
window.setTimeout(this.clickbuster.pop, 2500);
};

this.clickbuster.pop = function() {
this.clickbuster.coordinates.splice(0, 2);
};
/*If we catch a click event inside the given radius and time threshold then we call
 stopPropagation and preventDefault. Calling preventDefault will stop links
 from being activated.*/
this.clickbuster.onClick = function(event) {
for (var i = 0; i < clickbuster.coordinates.length; i += 2) {
 console.log(this);
    var x = clickbuster.coordinates[i];
    var y = clickbuster.coordinates[i + 1];
    if (Math.abs(event.clientX - x) < 25 && Math.abs(event.clientY - y) < 25) {
        event.stopPropagation();
        event.preventDefault();
    }
}
};

})(this);



document.addEventListener('click', clickbuster.onClick, true);
clickbuster.coordinates = [];

Answer 1

尝试使用new？

调用构造函数

new FastButton（el，function（）{}）;

试图实现Google的快捷按钮

1 个答案: