Question

我继续在python中获取no属性错误。我想为城市开设一个班级，以放入正在编写的程序中（我正在尝试一边工作一边学习python）。我基本上希望能够将数据放入城市的类中并在其他地方使用。我想，我需要知道如何从类中访问属性。我可能做错了很多，所以任何反馈都将对您有帮助

class City:

    def __init__(self, name, country, re_growth10):
        self.name = name #name of the city
        self.country = country #country the city is in
        self.re_growth10 = re_growth10 #City Real estate price growth over the last 10 years

    def city_Info(self):
        return '{}, {}, {}'.format(self.name, self.country, self.re_growth10)


Toronto = City("Toronto", "Canada", 0.03) #Instance of CITY
Montreal = City("Montreal", "Canada", 0.015) #Instance of CITY

user_CityName = str(input("What City do you want to buy a house in?")) #user input for city


def city_Compare(user_CityName): #Compare user input to instances of the class
    cities = [Toronto, Montreal]
    for City in cities:
        if City.name == user_CityName:
            print(City.name)
        else:
            print("We Don't have information for this city")
        return ""


print(City.name)

Answer 1

您会感到困惑，因为您拥有一个与班级City同名的变量。为避免这种情况，请对变量使用小写名称。更改此设置后，您将收到其他错误：

NameError：名称“ city”未定义

原因是您试图打印在函数内中定义的变量的名称，但是print语句在函数外。要解决此问题，请将最后一个print语句放在函数city_Compare内，然后调用该函数（您永远不会这样做）。

或将函数更改为return对象而不是打印它：

def find_city(name):
    cities = [Toronto, Montreal]
    for city in cities:
        if city.name == name:
            return city
    return None

city_name = input("What City do you want to buy a house in?")
city = find_city(city_name)

if city is not None:
    print(city.name)
else:
    print("We Don't have information for this city")

类型对象'...'没有属性名称'...'

1 个答案: