Question

this.statues.shift();正在隔离正确的元素并将其从数组中删除。但是，发生这种情况时，person.stoneed必须为false。有指针吗？谢谢。

代码：

class Medusa {
  constructor(name) {
    this.name = name;
    this.statues = [];
  }

  stare(person) {
    person.stoned = true;

    this.statues.push(person);

    if(this.statues.length > 3) {
      this.statues.shift();
    }
  }
};

class Person {
  constructor(name) {
    this.name = name;
    this.stoned = false;
  }
};

Answer 1

您需要保存移动的对象并设置其属性，如下所示：

if(this.statues.length > 3) {
  const unstoned = this.statues.shift();
  unstoned.stoned = false;
}

Answer 2

由于对象是通过引用传递的，因此可以使用shift的返回值直接进行内联

  <div class="pat-list">
    <mat-selection-list [multiple]="false">
      <mat-list-option *ngFor="let pat of patients" [value]="pat.patient_id" [routerLink]="['editDetails', pat.patient_id]" (click)="details(pat)">
        <mat-icon mat-list-icon><img src="{{ pat.photo ? pat.photo : pat.gender == 'male' ? 'assets/images/personIcon.png' : 'assets/images/personIcon.png'}}" style="font-size: 20px;width: 50px; height: 50px;" /></mat-icon>
        <div class="pat-text">
          <div mat-line class="pat-name">{{pat.name}}</div>
          <mat-icon matSuffix>keyboard_arrow_right</mat-icon>
        </div>
        <mat-divider></mat-divider>
      </mat-list-option>
    </mat-selection-list>
  </div>

Answer 3

 $update = encomendas::join('encomendas', 'encomendas_detalhes.id_encomenda', '=', 'encomendas.id')
        ->join('users', 'encomendas_detalhes.id_user', '=', 'users.id')
        ->join('encomendas_pagamentos', 'encomendas.id', '=', 'encomendas_pagamentos.id_encomenda')
        ->where('encomendas_pagamentos.entidade', $ENTIDADE)
        ->where('encomendas_pagamentos.referencia', $REFERENCIA)
        ->where('encomendas_pagamentos.valor', $VALOR);

    $update->estado = 2;

    $update->save();

或

if(this.statues.length > 3) { this.statues[0].stoned=false; this.statues.shift(); }

如何更改从数组中删除的元素的属性？

3 个答案: