Question

我正在尝试将以下数据框拆分为单独的列。我希望一栏中的所有文字和数字都在空白处分割。

df[0].head(10)

0                                                   []
1               [Andaman and Nicobar, 194, 52, 142, 0]
2        [Andhra Pradesh, 40,646, 19,814, 20,298, 534]
3                [Arunachal Pradesh, 609, 431, 175, 3]
4                   [Assam, 20,646, 6,490, 14,105, 51]
5                  [Bihar, 23,589, 8,767, 14,621, 201]
6                      [Chandigarh, 660, 169, 480, 11]
7              [Chhattisgarh, 4,964, 1,429, 3,512, 23]
8    [Dadra and Nagar Haveli and Daman, 585, 182, 4...
9                          [Daman and Diu, 0, 0, 0, 0]
Name: 0, dtype: object

如果我仅在空白处分割并展开，尽管数字已正确分割，但文本将分割为多列。由于不同观察值的文本跨越不同的列数，因此我无法再次合并它们。显然，解决方案是编写正确的“ regex”并拆分。我无法弄清楚所需的正则表达式，因此无法请求输入。

df1 = df[0].str.split(' ', expand= True)
df1.head(10)
    0   1   2   3   4   5   6   7   8   9
0   []  None    None    None    None    None    None    None    None    None
1   [Andaman    and     Nicobar,    194,    52,     142,    0]  None    None    None
2   [Andhra     Pradesh,    40,646,     19,814,     20,298,     534]    None    None    None    None
3   [Arunachal  Pradesh,    609,    431,    175,    3]  None    None    None    None
4   [Assam,     20,646,     6,490,  14,105,     51]     None    None    None    None    None
5   [Bihar,     23,589,     8,767,  14,621,     201]    None    None    None    None    None
6   [Chandigarh,    660,    169,    480,    11]     None    None    None    None    None
7   [Chhattisgarh,  4,964,  1,429,  3,512,  23]     None    None    None    None    None
8   [Dadra  and     Nagar   Haveli  and     Daman,  585,    182,    401,    2]
9   [Daman  and     Diu,    0,  0,  0,  0]  None    None    None

我期望的结果将是这样：

        0                                   1       2       3       4       5       6       7       8       9
    0   []                                  None    None    None    None    None    None    None    None    None
    1   [Andaman and Nicobar,               194,    52,     142,    0]      None    None    None    None    None
    2   [Andhra Pradesh,                    40,646, 19,814, 20,298, 534]    None    None    None    None    None
    3   [Arunachal Pradesh,                 609,    431,    175,    3]      None    None    None    None    None
    4   [Assam,                             20,646, 6,490,  14,105, 51]     None    None    None    None    None
    5   [Bihar,                             23,589, 8,767,  14,621, 201]    None    None    None    None    None
    6   [Chandigarh,                        660,    169,    480,    11]     None    None    None    None    None
    7   [Chhattisgarh,                      4,964,  1,429,  3,512,  23]     None    None    None    None    None
    8   [Dadra and Nagar Haveli and Daman,  585,    182,    401,    2]      None    None    None    None    None
    9   [Daman and Diu,                     0,      0,      0,      0]      None    None    None    None    None

Answer 1

您可以使用Public Function TestJohn2(derp As String) As String TestJohn2 = "test john2 " & derp End Function和str.replace重塑数据框。

str.extract

names = df[0].str.extract('(\D+)').replace('\[|,','',regex=True).rename(columns={0 : 'names'})


df_new = names.join(df[0].str.replace('\D+,','').str.strip(']').str.split(' ',expand=True))

如何根据条件将数据框列拆分为单独的列

1 个答案: