我在尝试使用此JPA tutorial时收到以下错误:
java.lang.NoSuchFieldError: NONE
at org.hibernate.ejb.QueryImpl.<init>(QueryImpl.java:609)
at org.hibernate.ejb.QueryImpl.<init>(QueryImpl.java:80)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:272)
at entity.PersonTest.insertAndRetrieve(PersonTest.java:50)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:76)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:50)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184)
at org.junit.runners.ParentRunner.run(ParentRunner.java:236)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:49)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
这是我的 persistence.xml :
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="examplePersistenceUnit" transaction-type="RESOURCE_LOCAL">
<class>entity.Person</class>
<properties>
<property name="hibernate.show_sql" value="false" />
<property name="hibernate.format_sql" value="false" />
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver" />
<property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/jpa_test" />
<property name="hibernate.connection.username" value="root" />
<property name="hibernate.connection.password" value="admin" />
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.hbm2ddl.auto" value="create" />
</properties>
</persistence-unit>
</persistence>
Person.java
package entity;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
public class Person {
@Id
@GeneratedValue
private int id;
private String firstName;
private char middleInitial;
private String lastName;
private String streetAddress1;
private String streetAddress2;
private String city;
private String state;
private String zip;
.
.
.
(getters and setters)
我的JUnit测试文件的一部分:
@SuppressWarnings("unchecked")
@Test
public void insertAndRetrieve() {
em.getTransaction().begin();
em.persist(p1);
em.persist(p2);
em.getTransaction().commit();
final List<Person> list = em.createQuery("select p from Person p")
.getResultList();
System.out.println("here...");
assertEquals(2, list.size());
我正在使用MySQL数据库,'person'表存在于数据库中。之后
em.getTransaction().begin();
em.persist(p1);
em.persist(p2);
em.getTransaction().commit();
我可以看到两个记录都插入到人员表中。但是在下一个声明中,它失败了。
编辑1: 我的构建路径中的JAR:
antlr-2.7.6.jar,
commons-collections-3.1.jar,
dom4j-1.6.1.jar, hibernate3.jar,
hibernate-annotations-3.5.5-Final.jar,
hibernate-commons-annotations-3.2.0.Final.jar,
hibernate-entitymanager-3.5.5-Final.jar,
hibernate-entitymanager-3.5.5-Final-sources.jar,
javaee-api-5.0-3.jar,
javassist-3.9.0.GA.jar,
log4j-1.2.12.jar,
mysql-connector-java-5.1.15.jar,
slf4j-api-1.6.1.jar,
slf4j-simple-1.6.1.jar,
hibernate-jpa-2.0-api-1.0.0-CR-1.jar
谁能告诉我我做错了什么?
感谢。
答案 0 :(得分:2)
答案 1 :(得分:2)
从类路径中删除ejb3-persistence.jar JAR文件。它包含JPA 1.0规范的接口。您需要保留hibernate-jpa-2.0-api-1.0.0-CR-1.jar JAR文件,因为它包含JPA 2.0规范的接口。
注意:如果您需要使用JPA 1.0,那么不要使用Hibernate 3.5.5,因为它包含JPA 2.0实现。将来,使用Maven进行依赖管理;它将帮助您避免这些问题。
<强>附录:强>
如果我从头开始设置Hibernate EntityManager 3.5.5(JPA 2),这些将是我要考虑的文件。以下列表是从the Hibernate documentation推断出来的:
文档中没有提到最后两个,但是是必需的。我没有看到任何其他JAR的需要,除了mysql-connector-java-5.1.15.jar和log4j-1.2.12.jar(两者都可以保留)。