我在这里缺少一些小东西,可以使用一个指针。我试图通过pymonogo
和其他pythonic数据库库来生成数据,以节省我的CRUD工作时间。下面是我遇到麻烦的代码。我想创建一个函数,该函数创建长度为n
的字典,但是我不知道如何适当地附加字典。如您所见,它仅输入生成的列表的最后一项。任何输入都会很棒!
import names
import random
import numpy as np
age_choices = np.arange(18, 90)
gender_choices = ['male', 'female']
salary_choices = np.arange(10000, 200000)
def create_data(n=20):
age_choices = np.arange(18, 90)
gender_choices = ['male', 'female']
salary_choices = np.arange(10000, 200000)
person_values = []
data_dict = {}
unique_id = 0
while unique_id < n:
age = random.choice(age_choices)
gender = random.choice(gender_choices)
salary = random.choice(salary_choices)
person_keys = ['id', 'name', 'gender', 'age', 'salary']
person_values = [unique_id, names.get_full_name(gender), gender, age, salary]
for k, v in zip(person_keys, person_values):
data_dict[k] = v
unique_id += 1
return person_values, data_dict
data_list, data_dict = create_data(5)
print(data_list)
print()
print(data_dict)
当前输出:
[4, 'Anthony Shultz', 'male', 29, 188503] # This is the last item of the list generated in the while loop
{'id': 4, 'name': 'Anthony Shultz', 'gender': 'male', 'age': 29, 'salary': 188503} # This is the "whole" dictionary generated but should have length 5 since n=5
所需的输出应该是长度为n
的字典,而不只是一个。
答案 0 :(得分:2)
您应该在函数中引入另一个变量,该变量将是列表或元组,并在每次创建变量时将每个data_dict
附加到变量中。您还应该在每次迭代的data_dict
循环中创建一个唯一的while
。例如(检查带有注释的行):
import names
import random
import numpy as np
age_choices = np.arange(18, 90)
gender_choices = ['male', 'female']
salary_choices = np.arange(10000, 200000)
def create_data(n=20):
age_choices = np.arange(18, 90)
gender_choices = ['male', 'female']
salary_choices = np.arange(10000, 200000)
person_values = []
all_data = [] # Make a list which will store all our dictionaries
unique_id = 0
while unique_id < n:
data_dict = {} # Create a dictionary with current values
age = random.choice(age_choices)
gender = random.choice(gender_choices)
salary = random.choice(salary_choices)
person_keys = ['id', 'name', 'gender', 'age', 'salary']
person_values = [unique_id, names.get_full_name(gender), gender, age,
salary]
for k, v in zip(person_keys, person_values):
data_dict[k] = v
all_data.append(data_dict) # Add newly created `data_dict` dictionary to our list
unique_id += 1
return person_values, data_dict, all_data # Return as desired
data_list, data_dict, all_data = create_data(5) # Just as an example
print(data_list)
print()
print(data_dict)
print()
print(all_data) # Print the output
这将产生字典列表,我假设您希望将其作为输出,例如:
[{'id': 0, 'name': 'David Medina', 'gender': 'male', 'age': 87, 'salary': 67957}, {'id': 1, 'name': 'Valentina Reese', 'gender': 'female', 'age': 68, 'salary': 132938}, {'id': 2, 'name': 'Laura Franklin', 'gender': 'female', 'age': 84, 'salary': 93839}, {'id': 3, 'name': 'Melita Pierce', 'gender': 'female', 'age': 21, 'salary': 141055}, {'id': 4, 'name': 'Brenda Clay', 'gender': 'female', 'age': 36, 'salary': 94385}]