我试图在用户设置依赖属性后,按名称绑定到DataTemplate中的HyperlinkButton。 (所有代码都在Silverlight 4中)我还是不知道要绑定到运行时的字段。我知道我可以在运行时创建DataTemplate作为一个具有正确绑定路径的字符串,并将其注入XmlReader,但这感觉很hacky。我继续从FindVisualChild函数获得的错误是“引用不是有效的可视化DependencyObject”。如何从datatemplate中获取对HyperlinkButton的引用,以便我可以设置绑定?
以下是我正在使用的代码:
XAML:
<sdk:DataGridTemplateColumn x:Class="CHK.WebMap.SL.Controls.DataGridURLTemplateColumn"
xmlns:sdk="http://schemas.microsoft.com/winfx/2006/xaml/presentation/sdk"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="400">
<sdk:DataGridTemplateColumn.CellTemplate>
<DataTemplate>
<HyperlinkButton x:Name="btnHyperlink" TargetName="_blank" />
</DataTemplate>
</sdk:DataGridTemplateColumn.CellTemplate>
</sdk:DataGridTemplateColumn>
代码隐藏:
public partial class DataGridURLTemplateColumn : DataGridTemplateColumn
{
public string NavigateUri
{
get { return (string)GetValue(NavigateUriProperty); }
set { SetValue(NavigateUriProperty, value); }
}
public static readonly DependencyProperty NavigateUriProperty =
DependencyProperty.Register("NavigateUri", typeof(string), typeof(DataGridURLTemplateColumn), new PropertyMetadata((s, e) =>
{
var context = s as DataGridURLTemplateColumn;
context.CellTemplate.LoadContent(); //create the ui elements
var hyperlinkButton = context.FindVisualChild<HyperlinkButton>(context) as HyperlinkButton;
hyperlinkButton.SetBinding(HyperlinkButton.NavigateUriProperty, new Binding(e.NewValue as string));
hyperlinkButton.SetBinding(HyperlinkButton.ContentProperty, new Binding(e.NewValue as string));
}));
public DataGridURLTemplateColumn()
{
InitializeComponent();
}
private childItem FindVisualChild<childItem>(DependencyObject obj) where childItem : DependencyObject
{
for (int i = 0; i < VisualTreeHelper.GetChildrenCount(obj); i++)
{
DependencyObject child = VisualTreeHelper.GetChild(obj, i);
if (child != null && child is childItem)
return (childItem)child;
else
{
childItem childOfChild = FindVisualChild<childItem>(child);
if (childOfChild != null)
return childOfChild;
}
}
return null;
}
}
答案 0 :(得分:5)
好的,我找到了答案。关于如何在DataTemplate中获取元素的问题。我实际上在代码示例中有它,但没有将结果保存到变量。
var hyperlinkButton = context.CellTemplate.LoadContent() as HyperlinkButton;